Write a balanced chemical equation describing the reaction of zinc and hydrochloric acid !
1. Write a balanced chemical equation describing the reaction of zinc and hydrochloric acid !
Answer :Reaction Metal Metal =Zn(s) Hydrochloric acid solution =HCl(aq) Zinc Chloride =ZnCl2(aq) Hydrogen Gas =H2 (g) Zn(s)+HCl (aq) -->ZnCl2(aq)+H2 (g) EquateZn(s) +2HCl(aq)-->ZnCL2 (aq) +H2 (g)
2. 3) 0.1 mol of lithium reacts with excess oxygen gas. (a) Write a balanced chemical equation for the reaction. (b) Calculate the mass of the product formed.
Jawaban:
Penjelasan:
(a) A balanced chemical equation for the reaction is:
2Li + O2 -> 2Li2O
(b) To calculate the mass of the product formed, we can use the molecular weight of lithium oxide (Li2O). The molecular weight of Li2O is 30.8 g/mol. Therefore, the mass of 0.1 mol Li2O is 3.08 grams.
3. Magnesium Sulfate could be made in the laboratory by neutralising a base, Magnesium Oxide, with an acid. What is the acid and write a balanced equation for the reaction.
The acid is sulphuric acid (H2SO4)
The reaction is:
[tex] MgO + H_2SO_4 => MgSO_4 + H_2O [/tex]H₂SO₄ (sulfuric acid)
Balanced equation of the reaction
[tex]MgO_{(s)} + H_2SO_4_{(aq)} \rightarrow MgSO_4_{(aq)} + H_2O_{(l)} [/tex]
4. Word equation for the reaction of astatine with iron
Jawaban:
Persamaan kata untuk reaksi astatin dengan besi
Penjelasan:
suruh apasih aku artiin aj
5. Write the complete balanced equation for the reaction between iron (III) oxide (Fe2O3) and water (H2O). You do not need to make the subscripts smaller; just write them out as regular numbers. For example: Fe2O3
Fe2O3 + 3 H2O ---> 2 Fe(OH)3
6. What is the equation of axis of symmetry of the given quadratic equation? * y = x2 – 8x - 9
Jawaban:
x = 4
Penjelasan dengan langkah-langkah:
x = -b/2a
= -(-8)/2(1)
= 4
Jawaban:
x = 4
Penjelasan dengan langkah-langkah:
semoga membantu:)
7. Write the word equation for the reaction between zinc and copper sulfate.
Jawaban:
Zn + CuSO4 ⇒ ZnSO4 + Cu
Penjelasan:
Zn has oxidation number equal to +2. Cu has oxidation number equal to +2. SO4 has oxidation number equal to -2.
8. the linear equationrepresenting "multinying anumber by 5 and addingto 8 it gives 20" isdash
Jawab:
[tex]x = \frac{12}{5}[/tex]
Penjelasan dengan langkah-langkah:
Apabila dibentuk ke dalam model matematika, kalimat matematikanya adalah
"Sebuah bilangan dikalikan dengan 5 kemudian ditambahkan 8 hasilnya adalah 20"
Misalkan
BIlangan tersebut adalah [tex]x[/tex]
Maka
[tex]5x + 8 = 20[/tex]
⇔ [tex]5x + 8 = 20[/tex]
⇔ [tex]5x = 20 -8[/tex]
⇔ [tex]5x = 12[/tex]
⇔ [tex]x = \frac{12}{5}[/tex]
∴ jadi bialngan yang ditanyakan adalah [tex]x = \frac{12}{5}[/tex]
9. 1. determine the differential equation foto the give circuit2. transform the equation into laplace transform3. determine the transfer function for the given circuit
Penjelasan dengan langkah-langkah:
jjnrnrjejeheh3u3hehndndjdhr
10. A curve is given by the equation x sin y y cos 2x!
Jawaban:
Sebuah kurva diberikan oleh persamaan x sin y y cos 2x!
11. Laundry bleach such as Clorox is a dilute solution of sodium hypocholorite, NaOCl. Write a balanced net ionic equation for the reaction of NaOCl with Na2S2O3. The OCl^- is reduced to Cholride ion and the S2O3^2- is oxidized to sulfate ion
no blok king my nam blaik
12. Write the quadratic equation given its solution x = 3, x = 4
x=3 and x=4
We get
x-3 = 0 and x -4 = 0
Next to do
(x-3)(x-4) = 0
x²-7x+12 = 0
Hope this will help
13. Given that the equation of the line representing each of the following linear graphs is in the form y=m+c, find the gradient m and state the y-intercept c.
Jawaban:
c.m+c, cari gradien m dan nyatakan perpotongan y c.
14. word equation for reaction between calcium and water
Jawaban:
Jawaban ada di gambar ya
Penjelasan:
Semoga membantu dan jadikan jawaban tercerdas ya :)
15. Question 2 40g of iron (III) oxide is reduced by carbon powder to form iron and carbon dioxide. (Relative atomic mass: 0 = 56, Fe = 56) (a) Write a balanced chemical equation for the reaction.
Iron (III) oxide = Fe2O3
Carbon = C
Iron = Fe
Carbon dioxide = CO2
Maka reaksi yang terjadi
Fe2O3 + C -> Fe + CO2
Untuk proses penyetaraan dapat dilakukan dengan metode langsung atau melalui setengah reaksi, berikut metode setengah reaksi dalam lingkungan asam.
Tuliskan masing-masing spesi yang mengalami oksidasi dan reduksi
Reduksi: Fe2O3 -> Fe
Oksidasi: C -> CO2
Selanjutnya ruas yang kekurangan atom O ditambah dengan H2O, ruas yang kelebihan atom H ditambah dengan H+ dan ruas yang muatannya belum setimbang ditambakan e (elektron) hingga muatan kedua ruas sama besar
Reduksi: Fe2O3 + 6H+ + 6e -> 2 Fe + 3 H2O x2
Oksidasi: C + 2 H2O -> CO2 + 4H+ + 4e x3
Sama kan koefisien e (elektron) masing-masing reaksi dengan mengalikan ekuivalen agar sama.
Reduksi: 2 Fe2O3 + 12H+ + 12e + 4 Fe + 6 H2O
Oksidasi: 3 C + 6 H2O -> 3 CO2 + 12H+ + 12e
Spesi yang sama pada kedua ruas dapat dihilangkan maka
Reaksi total; 2 Fe2O3 + 3 C -> 4 Fe + 3 CO2
16. the equation redox reaction below is unbalanced.a KBr + KMnO4 + b H2SO4 ➡ c Br2 + MnSO4 + d K2SO4 + H2Oafter being balanced the values of a, b, c dan d are...
maksudnya apa??.........…..
17. Given quadratic equation y = -×2-x+20a. Find what is the zero value
Using the quadratic formula
[tex] \frac{ - b \: ± \sqrt{ {b}^{2} - 4ac } }{2a} [/tex]
[tex]x = \frac{ - ( - 1)± \sqrt{( - 1 {)}^{2} - 4( - 1)(20)} }{2( - 1)} = [/tex]
[tex] x = \frac{1± \sqrt{81} }{ - 2} = [/tex]
[tex]x1= \frac{1 + 9}{ - 2} = - 5[/tex]
[tex]x2 = \frac{1 - 9}{ - 2} = 4[/tex]
ANSWER:
X1=(-5)
X2=4
18. A 1.000 mol sample of propane, a gas used for cooking in many rural areas, was placed in a bomb calorimeter with excess oxygen and ignited. The initial temperature of the calorimeter was 25.000 °C and its total heat capacity was 97.13 kJ °C-1. The reaction raised the temperature of the calorimeter to 27.282 °C. (a) Write the balanced chemical equation for the reaction in the calorimeter. (b) How many joules were liberated in this reaction? (c) What is the heat of reaction of propane with oxygen expressed in kilojoules per mole of C3H8 burned?
Kimia Kelas XI
Termokimia
Mohon koreksinya ya! Semoga membantu :) Tetap semangatt ^^
19. 2. A reaction between 70.0 g of copper(II) oxide and 50 mL of 2.0 M nitric acid produces copper(II) nitrate, Cu(NO3)2 and water. (a) Write the balanced chemical equation for the above reaction. (b) Determine the limiting reactant. (c) Calculate the mass of excess reactant after the reaction. (66.02 g) (d) Determine the percentage yield if the actual mass of copper(II) nitrate obtained from the reaction is 8.5 g (90.62%)
Jawaban:
a. The balanced chemical equation for the reaction above
CuO + 2[tex]HNO_{3}[/tex] → [tex]Cu(NO_{3})_{2}[/tex] + [tex]H_{2}O[/tex]
b. he limiting reactant: nitric acid ([tex]HNO_{3}[/tex])
c. the mass of excess reactant after the reaction = 67,97 g
d. the percentage yield if the actual mass of copper(II) nitrate obtained from the reaction is 8.5 g = 50,47%
Penjelasan:
Persamaan reaksi dari reaksi tersebut adalah:
CuO + 2[tex]HNO_{3}[/tex] → [tex]Cu(NO_{3})_{2}[/tex] + [tex]H_{2}O[/tex]
mol CuO = [tex]\frac{massa}{Mr}[/tex]
= [tex]\frac{70}{79,5}[/tex]
= 0,88 mol
mol [tex]HNO_{3}[/tex] = V x M
= 50 mL x 2 M
= 100 mmol = 0,1 mol
Pereaksi pembatas dapat ditentukan dengan membagi mol reaktan dengan keofisienya. Reaktan yang hasil baginya lebih kecil merupakan pereaksi pembatas.
[tex]\frac{mol CuO}{koef CuO}[/tex] = [tex]\frac{0,88}{1}[/tex] = 0,88
[tex]\frac{mol HNO_{3} }{koef HNO_{3} }[/tex] = [tex]\frac{0,1}{2}[/tex] = 0,05
Hasil bagi yang lebih kecil adalah [tex]HNO_{3}[/tex] jadi pereaksi pembatasnya adalah [tex]HNO_{3}[/tex]. Sehingga:
mol CuO yang bereaksi = [tex]\frac{koef CuO}{Koef HNO_{3} }[/tex] x mol [tex]HNO_{3}[/tex]
= [tex]\frac{1}{2}[/tex] x 0,05
= 0,025 mol
mol [tex]Cu(NO_{3})_{2}[/tex] hasil reaksi = [tex]\frac{koef Cu(NO_{3})_{2} }{Koef HNO_{3} }[/tex] x mol [tex]HNO_{3}[/tex]
= [tex]\frac{1}{2}[/tex] x 0,05
= 0,025 mol
mol [tex]H_{2}O[/tex] hasil reaksi = [tex]\frac{koef H_{2}O }{Koef HNO_{3} }[/tex] x mol [tex]HNO_{3}[/tex]
= [tex]\frac{1}{2}[/tex] x 0,05
= 0,025 mol
CuO + 2[tex]HNO_{3}[/tex] → [tex]Cu(NO_{3})_{2}[/tex] + [tex]H_{2}O[/tex]
Awal : 0,88 mol 0,05 mol
Reaksi : 0,025 mol 0,05 mol 0,025 mol 0,025 mol
--------------------------------------------------------------------------------------------
Akhir : 0,855 mol - 0,025 mol 0,025 mol
Reaktan yang bersisa diakhir reaksi adalah CuO sebanyak 0,855 mol. Massa CuO = mol x Mr
= 0,855 x 79,5
= 67,97 g
[tex]Cu(NO_{3})_{2}[/tex] yang dihasilkan adalah 0,025 mol.
Massa [tex]Cu(NO_{3})_{2}[/tex] = mol x Mr
= 0,025 x 171,5
= 4,29 g
%[tex]Cu(NO_{3})_{2}[/tex] = [tex]\frac{4,29}{8,5}[/tex] x 100%
= 50,47%
Materi tentang pereaksi pembatas dapat disimak pada link:
https://brainly.co.id/tugas/40947892
#BelajarBersamaBrainly
20. the correct equation of electrolyte ionization reaction in water is
the correct equation if electrolyte ionization reaction in water is H2 + O2 = H2O.
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