find the total area of the shaded region in the figure
1. find the total area of the shaded region in the figure
Jawaban:
The total area of the shaded reagion in the figure = 76 cm
Penjelasan dengan langkah-langkah:
Total area of the shaded region:
[tex] = \frac{(5 + 7 + 6) \times 8}{2} + \frac{(7 + 6) \times 8}{2} - 2 \times \frac{8 \times 6}{2}[/tex]
[tex] = 72 + 52 - 48 = 76 \: {cm}^{2} [/tex]
2. Find the area of the shaded region.
Sector area AOB :
θ/360° × πr²
= 58°/360° × π(5)²
= 29°/180° × 25π
= 145π/36
= 12.65 cm²
Missing side (AT) of triangle TAO:
tan(58°) = AT/5
AT = 5tan(58°)
AT= 8 cm
Area of triangle TAO:
1/2 × base × height
= 1/2 × AO × AT
= 1/2 × 5 × 8
= 20 cm²
Shaded region:
TAO - AOB
= 20 cm² - 12.65 cm²
= 7.35 cm²
3. Find the area of the blue region
Penjelasan dengan langkah-langkah:
Area of trapezium = (10 + 14) × 12 ÷ 2 cm²
Area of trapezium = 144 cm²
Area of triangle = 14 × 12 ÷ 2 cm²
Area of triangle = 84 cm²
Area of blue region = 144 cm² - 84 cm²
Area of blue region = 60 cm²
semoga membantu ya
4. Find the area of the shaded region in this diagram. Give your answer correct to 1 decimal place.
Jawaban:
157/2 atau 78 1/2 atau 78,5
Penjelasan dengan langkah-langkah:
diket:5cm
dity:L....?
jawab:L=πxrxr
=3,14x5x5
=3/14x5x5
=157/2 atau 78 1/2 atau 78,5
Maap klo slah
5. Find the number of moles of the indicated species: a) 333 mg of Na2B4O7.10H20
Jawaban:
Penjelasan:
[tex]\text{Na}_2\text{B}_4\text{O}_7.10\text{H}_2\text{O}[/tex]
Mr = 2Na + 4B + 8O + 20H
Mr = 2(23) + 4(11) + 17(16) + 20(1)
Mr = 46 + 44 + 272+ 20
Mr = 382
[tex]n = \frac{m}{Mm}\\n = \frac{333}{382}\\n = 0,87 \times 10^-3 \ \text{mol}[/tex]
6. a card is drawn from a deck of cards. Find the probability of getting 3 of diamond
Number of cards = 52
n(S) = 52
There's only one 3 of diamond,
n(P) = 1
Probability = 1/52
7. find the area of shaded region
Jawaban:
The example is wrong, It doesn't make sense
1. 9750 cm2
2.
Penjelasan dengan langkah-langkah:
1.
[tex] \frac{3}{4} \times ( \frac{22}{7} \times {35}^{2} ) \\ \frac{3}{4} \times ( \frac{22}{7} \times 3850 ) \\ \frac{3}{4} \times 12100 \\ = 9750 cm {}^{2} [/tex]
2.
[tex] = 3.14 \times {12}^{2} \\ = 3.14 \times 144 \\ 452.16cm {}^{2} [/tex]
[tex] = \frac{22}{7} \times {7}^{2} \\ = \frac{22}{7} \times 49 \\ = 154cm {}^{2} [/tex]
[tex]452.16 - 164 = 288.16cm {}^{2} [/tex]
Sorry if I'm wrong
8. Need this urgentlyThe diagram shows a square inscribed inside a circle, centre 0. Given that the area of the shaded region is 161 cm2, find the perimeter of the shaded region. Give your answer in the form (a + b) cm. [3]
Jawab:
O is also center of square, so angle O = 90° (intersection of diagonals)
shaded area = [tex]\frac{90}{360}[/tex] × area of circle
16π = [tex]\frac{90}{360}[/tex] × πr²
r² = 16 ÷ [tex]\frac{90}{360}[/tex]
r = [tex]\sqrt{64}[/tex]
r = 8 cm
perimeter = 2×radius + 1/4 circumference of circle
= 2r + 1/4 × π × 2r
= 2 × 8 + 1/4 × π × 2 × 8
= (16 + 4π) cm
9. the figure is made up of a semicircle in a quadrant. find the area of the shaded region
I hope this helps...................
10. the figure is made up of two identical quadrants and a square. find the area of the shaded region.
[tex] \frac{1}{4} [/tex] x 21 + [(21 x 21) -
11. Each day Annabel eats rice, potato or pasta. Independently of each other, the probability that she eats rice is 0.75, the probability that she eats potato is 0.15 and the probability that she eats pasta is 0.1. Find the probability that, in any week of 7 days, Annabel eats pasta on exactly 2 days.
Kalo menurut saya ... 10/14 days
Kalo salah maaf ...soalnya nggak ngerti bahasa INDONESIA nya
12. For each of the following figures, find the area of the blue region(s).
c. 45 cm²
d. 150,96 cm²
Penjelasan dengan langkah-langkah:
c. L = L.trapesium - L.segitiga
= 1/2 x (9+17) x 12 - 1/2 x 17 x 6
= 1/2 x 16 x 12 - 51
= 96 - 51
= 45 cm²
d. L = L.jajaran genjang - L.lingkaran
= 12 x 22 - 3,14 x 6 x 6
= 264 - 113,04
= 150,96 cm²
13. If z is a standard normal variable, find the probability that z lies between -1.10 and -0.36 !
Jawaban:
YNTKTS :((((((((((((((((
14. Pls help ThxThe diagram shows a square inscribed inside a circle, centre 0. Given that the area of the shaded region is 161 cm?, find the perimeter of the shaded region. Give your answer in the form (a + b) cm. [3] In the figure, ABCD is a square with side length equals 5 cm. Calculate the area of the shaded region. [3] B 'o D с
Jawab:
(4pi+16)cm
Penjelasan dengan langkah-langkah:
A= 16picm^2
16pi= 1/4 x pi x r^2
16= 1/4r^2
64=r^2
/64 = 8
r = 8
c= 1/4 x pi x (8x2)
c= 4pi
p= (4pi+16)cm
15. The un-shaded region of the following figure is the feasible region of a system of linear inequalities. The maximum value of (2x + 2y – 5) is attained at what point in the feasible region? a. Show the system of linear inequalities used in finding the maximum value b. Show the coordinates and the solutions made to get the coordinates at the corner points in the feasible region. c. Show the table of values 2x + 2y – 5.
Jawab:
chk it, rapikan, feedback
Penjelasan dengan langkah-langkah:
16. how to do it？find the area of unshaded region...
Lihat Gambar
Phytagoras
[tex]A = 10\sqrt{2} [/tex]
[tex]B= \frac{1}{2}A \\ B = 5 \sqrt{2} [/tex]
[tex]C = \frac{1}{2} B \\ C=2,5 \sqrt{2} [/tex]
Phytagoras
[tex]E=5[/tex]
[tex]F=5[/tex]
Kesebangunan Segitiga
[tex] \frac{C}{D} = \frac{B}{E} \\ D= \frac{C.E}{B} \\ D=2,5[/tex]
Luas kotak Dalam
[tex]L = (2D)(2D) \\ L=(2(2,5))(2(2,5) \\ L=5.5 \\ L=25[/tex]
17. The figure shows circle of radius 14 cm with one quadrant removed, touching the sides of square. Find @ the perimeter of the unshaded region, (i) the area of the unshaded region, (iii) the area of the shaded region.
di antara nilai p berikut yang memenuhi proporsi p:7 21:49 adalah
18. Find the volume of the solid obtained by rotating the region bounded by two parabolas
Penjelasan:
jhhhhhh3j33ju2u2u2u2u2u2u2u
19. Fill in the blanks with the comparative forms of the adjectives indicated in brackets.
Fill in the blanks with the comparative forms of the adjectives indicated in brackets
---NewestMore refreshingBiggerMore goodMore delicateTidierMore accurate20. The probability of drawing a green ball in an experiment is 3/8. What is the probability of not drawing a green ball?
Jawaban:
5/8
Penjelasan dengan langkah-langkah:
1-3/8
5/8
semoag membantu!
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