Factor that depend heat is A.mass, temperature, and weight B.mass, specific latent heat, weight C.mass, specific latent heat, temperature D.mass, specific letent heat, weight
1. Factor that depend heat is A.mass, temperature, and weight B.mass, specific latent heat, weight C.mass, specific latent heat, temperature D.mass, specific letent heat, weight
Jawaban:
c
Penjelasan:
seemoogaa meemmmbannntuuu
2. berapa specific heat dari cabai merah???? totong ya....
Skala Scoville, adalah ukuran tentang pedasnya cabai. Jumlah Satuan pedas Scoville (SHU) menunjukkan jumlah capsaicin yang ada padanya.
krn begitu banyak jenis cabai merah dan kandungan capsaicin yang berbeda pula, kamu bisa melihat tabel SHU di:
id.m.wikipedia.org/wiki/Skala_Scoville
ok, smoga membantu, salam...
3. How many joules are energy required to melting 100g ice 0"C becomes water 50'C. Specific laten heat of fusion = 336.000 J/Kg Specific heat capacity of water = 4200 J/Kg "C
Jawaban:
energy required 54.600joule or 54,6KJ
Penjelasan:
cara difoto
4. Answer key of reading power by longman
Jawaban:
kunci jawaban "kekuatan membaca" oleh logman
Jawaban:
kunci jawaban kekuatan membaca oleh longmen
Penjelasan:
semoga membantu
5. ....specific reasons and examples to support your answer!
Jawaban:
Usespecific reasons and examples to support your answer!
Maaf klo salah^_^
6. a 63.5 sample of an unindentified metal absorb 355 J of heat when it's temperature changed by 4.56°C. calculate the specific heat capacity of the metal
Jawaban:
maaf kalo salah......
................
7. If the specific heat of water is 1000 J/kg°C, how much heat is required to heat 2 kg of water from 230°C to 1000°C?
Jawaban:
Penjelasan:
t= 1000-230= 770 celcius
m= 2kg
1000J/kg°C x 770 x 2 = 1.540.000 joule
8. 2. Calculate the amount of heat needed to raise the temperature of 400 g steel from 200C to 1400C! (the specific heat of steel is 460 J/kg0C)
m = 400 g = 0,4 kg
Δt = 1400 - 200 = 1200
c = 460
Q = M . C . Δt
= 0,4 . 460 . 1200
= 220.800 Joule
9. ATTITUDE is THE KEY, what the answer ?
Jawaban:
pernyataan evaluatif terhadap objek, orang atau peristiwa. ini yng bhs inggris (Evaluative statements on objects, people or events)
Penjelasan:
maaf jika salah
10. looked for-in-she-key-her-yesterday-yard-the answer :.....................
She looked for her key yesterday in the yard
She looked for her key in the yard yesterday
11. An object with a mass of 200 g has a heat capacity of 104 J/oC. The specific heat of the substance is
Jawaban:
520 J/Kg C
diketahui :
m = 200 = 0,2
C = 104 J/C
ditanya :
c = ?
dijawab :
c = C/m
c = 104/0,2
c = 520 J/Kg C
12. An object with a mass of 200 g has a heat capacity of 104 J/oC. The specific heat of the substance is
Jawaban:
520 J/Kg C
Penjelasan:
diketahui :
m = 200 = 0,2
C = 104 j/kg C
ditanya :
c = ..... ?
dijawab :
c = C/m
= 104/0,2
= 520 j/kg C
13. An object with a mass of 200 g has a heat capacity of 104 J/oC. The specific heat of the substance is.
An object with a mass of 200 g has a heat capacity of 104 J/°C. The specific heat of the substance is 20.8 J/kg°C
Solution:
Known:
m = 200 gram = 0,2 kg
C = 104 J/°C
Asked:
c = ...?
Answer:
c = m × c
= 0,2 × 104
= 20.8 J/kg°C
So, the specific heat of the substance is 20.8 J/kg°C.
14. 5. Calculate the amount of heat needed to raise the temperature of 1.5 kg water from 300C to 800C. (specific heat of water= 1 kcal/kg0C)
Jawaban:
750.000 kal = 750 kkal
Penjelasan:
Diketahui :
m = 1,5 kg
c = 1 kkal/(kg °C)
ΔT = T2 - T1 = 800°C - 300°C = 500°C
Ditanya : Q = ... kal?
Jawab :
Q = m c ΔT
Q = 1,5 kg (1 kkal/(kg °C)) (500°C)
Q = 750 kkal
Q = 750.000 kal
#Jadikan Jawaban Terbaik
15. The heat required to raise the temperature of 7 kg of water from 10 oC to 80 oC and The specific heat of the water 4200 J/kg oC is
The heat required to raise the temperature of 7 kg of water from 10°C to 80°C and The specific heat of the water 4.200 J/kg°C is 2.058.000 Joule.
Solution:Known:
m = 7 kg
∆T = 80°C – 10°C = 70°C
c = 4.200 J/kg°C
Asked:
Q = ...?
Answer:
Q = m × c × ∆T
= 7 × 4.200 × 70
= 2.058.000Jouleor 2.058kJ.
16. A piece of metal weighing 4 kg is heated from 25 Degrees Celsius to 55 degrees Celsius. The heat needed is 12,000 Joules. A. Calculate the heat capacity of the metal b. Calculate the specific heat capacity of the metal.
A.
Q = C . delta T
12000 = C . ( 55 - 25 )
C = 400 J/C
B.
C = m . c
400 = 4 . c
c = 100 J/KgC
17. An object with a mass of 200 g has a heat capacity of 104 J/oC. The specific heat of the substance is
An object with a mass of 200 g has a heat capacity of 104 J/°C. The specific heat of the substance is 20.8J/kg°C
Solution:Known:
m = 200 gram = 0,2 kg
C = 104 J/°C
Asked:
c = ...?
Answer:
c = m × c
= 0,2 × 104
= 20.8J/kg°C
So, the specific heat of the substance is 20.8 J/kg°C.
18. 500 grams of ice at -10^oC will be melted down to become water at 5^oC. If the specific heat of ice is 0.5 cal/gr^oC, the heat of fusion for ice is 80 cal/gr and the specific heat of water is 1 cal/gr^oC. Determine the amount of heat needed * 20 poin
Jawaban:
Penjelasan:
- heat absorbed to reach 0 degree C
[tex]Q_1=mc\Delta T=500 gram\times 0.5 cal/gramK\times (0-(-10))K=2500 cal[/tex]
- heat absorbed to make it water
[tex]Q_2=mL=500gram\times 80 cal/gram=40000 cal[/tex]
- heat absorber to reach 5 degree C of water
[tex]Q_3=mc\Delta T=500 gram times 1 cal/gramK\times (5-0)K=2500 cal[/tex]
total heat absorbed
[tex]Q=Q_1+Q_2+Q_3=2500cal+40000cal+2500cal=45000cal[/tex]
19. A 15.75-g piece of iron absorbs 1086.75 joules of heat energy, and its temperature changes from 25°C to 175°C. Calculate the specific heat capacity of iron.
Penjelasan:
may the solution help you and don't forget to follow me please (^^)
20. How much heat is required to raise the temperature of 500g water 20°c to 80°c,if the specific heat of water is 4200 J/kg°c
Semoga jawaban ini dapat membantu. ☺
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