the gradient of the line perpendicular to line a is ...
1. the gradient of the line perpendicular to line a is ...
Jawaban:
Perpendicular Lines (HIGHER TIER)
Penjelasan:
Two lines are perpendicular if one is at right angles to another- in other words, if the two lines cross and the angle between the lines is 90 degrees. If two lines are perpendicular, then their gradients will multiply together to give -1
Semogamembantu(๑•ᴗ•๑)♡mohonmaafjikajawabansayakurangtepat
2. Look at the picture below! Line AB is perpendicular to line ....
Jawab:
Line AB is perpendicular to line BD
maaf kalau salah hehe
3. The area of a triangle is 528cm2. the length of its base is 33cm. calculate the perpendicular height of the triangle.
Diketahui:
Luas segitiga = 528 cm²
Panjang alas = 33 cm
Tinggi = ?
[tex]luas \: = 528 \\ \frac{1}{2} \times a \times t = 528 \\ \frac{1}{2} \times 33 \times t = 528 \\ t = \frac{528 \times 2}{33} \\ t = 32[/tex]
Jadi, tinggi segitiga adalah 32 cm.
Jawab:
32
Penjelasan dengan langkah-langkah:
L=528
a= 33
L= a*t/2
528= 33*t/2
1056=33t
t= 1056/33
t=32
4. given the three points A = (-2,6) , B = (4,-6) and C = (1,2), consider the triangle ABC and let M be the point on AC so that BM is the altitude through B perpendicular to AC. Likewise let N be the point on AB so that CN is the altitude through C perpendicular to AB. a) find M b) find N
Vertices, A = (-2,6), B = (4,-6), C = (1,2)
Transform into Positional vector,
A = -2i + 6j
B = 4i - 6j
C = i + 2j
Point M is on Line AC, such that Line BM perpendicular to AC.
Therefore using scalar vector projection give us length of AM or CM
[tex]|\overline{AM}|=\frac{\overline{AB}.\overline{AC}}{|\overline{AC}|}[/tex]
AB = i(4+2) + j(-6 - 6) = 6i - 12j
AC = i(1+2) + j(2 - 6) = 3i - 4j
|AC| = 5
[tex]|\overline{AM}|=\frac{18+48}{5}[/tex]
[tex]|\overline{AM}|=\frac{66}{5}[/tex]
Distance between point A and M are 66/5
[tex]\frac{\overline{AC}}{|\overline{AC}|}= \frac{3}{5}i-\frac{4}{5}j[/tex]
Therefore vector AM,
[tex]\overline{AM}= \frac{198}{25}i-\frac{264}{25}j[/tex]
Point M,
[tex]A+\overline{AM}= \frac{-50+198}{25}i+\frac{150-264}{25}j[/tex]
[tex]M= \frac{148}{25}i-\frac{114}{25}j[/tex]
Which is not on Line AC.
By projecting line AC to AB,
AB = 6i - 12j
AC = 3i - 4j
|AB| = √(144+36) = 6√5
[tex]|\overline{AN}|=\frac{\overline{AB}.\overline{AC}}{|\overline{AB}|}[/tex]
[tex]|\overline{AN}|=\frac{66}{6\sqrt{5}}= \frac{11\sqrt{5}}{5} [/tex]
[tex]\frac{\overline{AB}}{|\overline{AB}|}= \frac{\sqrt{5}}{5}i-\frac{2\sqrt{5}}{5}j[/tex]
Vector AN,
[tex]\frac{11\sqrt{5}}{5} \frac{\overline{AB}}{|\overline{AB}|} = \frac{55}{25}i - \frac{110}{25}j [/tex]
[tex] \overline{AN} = \frac{55}{25}i - \frac{110}{25}j [/tex]
Point N,
[tex] A + \overline{AN} = \frac{-50+55}{25}i + \frac{150-110}{25}j [/tex]
[tex] N = \frac{1}{5}i + \frac{40}{25}j [/tex]
5. Find the equation of the line passing through the point (6,3) that is perpendicular to the line 4x−5y=−10. Step 1: Find the slope of the line 4x−5y=−10.What would the perpendicular slope be?Step 2: Use the slope to find the y-intercept of the perpendicular line.Step 3: Write the equation of the line that passes through the point (6,3) that is perpendicular to the line 4x−5y=−10
Find the equation of the line passing through the point (6,3) that is perpendicular to the line 4x - 5y = -10?
Solution :
4x - 5y = -10
- 5y = 4x - 10
Divide both sides by -5
y = (4/-5)x - (10/-5)
y = (-4/5)x + 2
From the slope intercept form we get
m = - 4/5
The slope of a perpendicular is a negative inverse of - 4/5
m = (5/4)
Slope intercept form for the perpendicular line is
y = (5/4) x +b
Solve for b using (6, 3)
3 = (5/4) (6) + b
3 = 30/4 + b
b = 3 - 30/4
b = (12 - 30)/4
b = -18/4
b = -9/2
So the perpendicular line is y = (5/4)x - 9/2
The equation of the line passing through the point (6,3) that is perpendicular to the line 4x-5y=-10 is y = (5/4)x - 9/2.
6. A straight wire carrying a current of 2A is placed in a 0.5 T magnetic field perpendicular to the current. If the Lorentz force acting on the wire is 2N, then the length of the wire is..tolong jawab yaa makasihh
Given :
I = 2 Amphere
B = 0,5 Tesla
F = 20 Newton
Asked : The Length of Wire ?
Answer :
[tex]\displaystyle F = B\times I \times L\\\\20 = 0,5 \times 2 \times L\\\\20 = 1 \times L\\\\20 = L[/tex]
So, The length of wire is 20 Meters
7. 11. In the diagram, a flag is hung on a mast AB that is projected out of a building. AB = 5 m, AF = 12 m and ¿FAB = 113°. Find (a) the perpendicular distance from B to the vertical wall of the building, (b) the height of B above the ground.
SayaTataU47901467ya0
8. AB is a chord of a circle, centre 0 and with radius 17 cm. Given that AB = 16 cm, find the perpendicular distance from 0 to AB.
Jawaban:
jwbny I DONT NO YA!,OKE JADI SAYA GAK TAU
9. 7. ABC is a right-angled triangle with AB perpendicular to BC. The coordinates of the points A, B and Care (-5,0), (x,-5) and (3,-2) respectively. Find the possible values of x.
Jawaban:
panjang AB = √{ (x+5)²+(-5+0)²} = √((x+5)²+25)
panjang BC = √{(3-x)²+(-2+5)²) = √{(3-x)²+9}
panjang AC = √{(3+5)²+(-2-0)²} = √68
sesuai hukum phytagoras yang berlaku untuk segitiga siku²
maka 68 = (x+5)²+25 + (3-x)²+9
68-34 = x²+25+10x+9+x²-6x
68-68= 2x²+4x
x = -2 atau x = 0
semoga paham
10. a stream of light with wavelenght of 600 nm is perpendicular incident on a grid with 300 scratches in every mm the maximum order observed is
The maximum order observed is 5
Further explanationA diffraction grating is used to scatter polychromatic light into the color of its components.
The gap between scratches has a distance called the lattice constant (r)
The path difference (C) formed between two gaps is d sin θ
Can be formulated
[tex]\rm \boxed{\bold{C=d~sin~ \theta}}[/tex]
[tex]\rm r=\dfrac{1}{N}~(N=lines/cm~of~the~grid)[/tex]
A stream of light with wavelength of 600 nm is a perpendicular incident on a grid with 300 scratches in every mm
So it is known:
λ = 600 nm = 6 x 10⁻⁷ m
N = 300 lines / mm
then the lattice constant
[tex]\rm r=\dfrac{1}{N}\\\\r=\dfrac{1}{300}\\\\r=3.10^{-6}~m[/tex]
Maximum Order:
[tex]\rm r~sin~\theta=n.\lambda\\\\sin~\theta=\dfrac{n.\lambda}r}\\\sin~\theta=n.\dfrac{6.10^{-7}}{3.10^{-6}}\\\\sin~\theta=n.0.2[/tex]
The maximum value of the sine function = 1, so that the maximum order
[tex]\rm 1=n\times 0.2\\\\n=\dfrac{1}{0.2}=\boxed{\bold{5}}[/tex]
Learn moreDiffraction grating
https://brainly.co.id/tugas/22653669
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Detailed answer
Grade :11th class
Subjects: Physics
Chapter: Light Waves
Code: 11.6.10
Keywords: diffraction grating, lattice constant
11. Parcel A has 2 parallel sides that measure 20m and 35m. The perpendicular between each side is 50m. Find the area of the parcel.
JAWABAN:2 + 20 = 22.= 22 + 35 = 57.= 57 + 50 = 107.= 107.SEMOGAMEMBANTU
12. In the diagram, AC = 20 cm, CD = 22 cm andAE = 16 cm. AE is perpendicular to CD and BD is perpendicular to AC. Find the length of BD.
Jawab: DB = 17,6 cm
Penjelasan dengan langkah-langkah:
DB x AC = AE x DC
DB = AE x DC / AC
= 16 x 22 / 20
= 17,6 cm
Penjelasan dengan langkah-langkah:
BD/20 = 16/22
BD/20 = 8/11
BD = 20 x 8/11
BD = 160/11
BD = 14,5454545454.....
BD=14,54cm13. find the equation of the line that is perpendicular to the line y = 3x - 1 through the point 12,4
Jawab:
x + 3y - 24 = 0Penjelasan dengan langkah-langkah:
The gradient (m) of a line perpendicular to another line is
-1 / the gradient of another line
y = 3x - 1, therefore m₁ = 3
-1 / (m₁) =
-1 / (3) =
m₀ = -1/3
Point passed = (12, 4)
x₁ = 12y₁ = 4With this equation, find the equation of line:
y-y₁ = m₀(x-x₁)
y-4 = -1/3(x-12)
y-4 = -1/3)x + 4
y = -1/3)x + 4 + 4
y = -1/3)x + 8
3y = -x + 24
or
x + 3y - 24 = 0 ✅嘉誠
14. 5 a. From the following statement, write true or false for the property of the rectangle The opposite sides are equal and parallel. Two diagonals are equal, bisect each other, and are perpendicular. The opposite angles are equal and both diagonals are the bisector of the angle. The adjacent angles are supplementary.
Jawaban:
b.inggris,............
15. Medians BD and CE of triangle ABC are perpendicular, BD = 8, and CE = 12. The area of triangle ABC is.
The correct answer is 64
16. Triangle ADB is an equilateral triangle. BCD = 54º and AB isperpendicular to BC. Find ADC.
Penjelasan:
ABD = BDA = DAB
ABD = 180° / 3
ABD = BDA = 60°
ABC = ABD + DBC
DBC = ABC - ABD
DBC = 90° - 60°
DBC = 30°
BDC = 180° - 30° - 54°
BDC = 96°
ADC = ADB + BDC
ADC = 60° + 96°
ADC = 156°
17. "earthquake causes perpendicular layers motion of the earth". change the sentence into passive voice!
Answer:
Perpendicular layers motion of the earth iscaused earthquake
Explanation:
Kalimat di atas adalahSimplePresentTense
Rumus = S + to be + V3
Contoh:
ActiveRifky buys a comicRifky membeli sebuah komikPositivea comic is bought by Rifkykomik dibeli oleh RifkyNegativea comic is not bought by Rifkysebuah komik tidak dibeli oleh RifkyInterrogativeis a comic bought by Rifky ?apakah sebuah komik dibeli oleh Rifky #bisabahasainggerisCMIIW
Semogabermanfaat^_^
Passive VoiceActive : Earthquake causes perpendicular layers motion of the earth.
Passive : Perpendicular layers motion of the earth is caused by earthquake.
ーーーーーーーーーーーー
PrefacePassive voice adalah salah satu grammatical voice dalam tata bahasa Inggris.
Dalam passive voice atau kalimat pasif, subjek kalimat adalah patient atau penerima aksi yang dilakukan oleh agent atau pelaku aksi.
Mari kita lihat kalimat aktif berikut:
John reads a book.
John = agent → yang melakukan aksiread = verb → aksia book = patient → penerima aksiKalimat pasif mempunyai konstruksi:
patient + conjugated be + pastparticiple of verb ( + by agent)
Jadi, kalimat pasif dari John reads a book adalah:
A book is read by John.
A book = patientis = conjugated beread = past participle of the verb readJohn = agentーーーーーーーーーーーー
ExplicationEarthquake causes perpendicular layers motion of the earth.
Earthquake = agentcauses = verbperpendicular layers motion of the earth = patientJadi, pasif dari kalimat tersebut adalah
Perpendicular layers motion of the earth is caused by earthquake.
Konjugasi be yang digunakan adalah is karena :
causes = verb + -s → present simple; be = am / is / aremotion = tunggal; be = isーーーーーーーーーーーー
Pelajari lebih lanjut:https://brainly.co.id/tugas/22143449https://brainly.co.id/tugas/23245726https://brainly.co.id/tugas/22444026ーーーーーーーーーーーー
DetailsYear : 9
Subject : English
Category : Structure and Written Expression
Sub-category : Passive Voice
Code : 9.5.8
Keywords : Passive, change into passive
18. definition of constructing imperative sentences
Imperative sentence is a sentence type used to create commands, requests, or directions.
19. earthquake causes perpendicular layers motion of the earth"". change the sentence into passive voice! *
Jawaban:
Active Voice: earthquake causes perpendicular layers motion of the earth.
Passive Voice: Perpendicular layers motion of the earth is caused by earthquake.
Penjelasan:
Kalimat menggunakan bentuk Passive dari Simple Present Tense:
(+) Subject + Tobe (is/am/are) + Verb-3
Semoga membantu ya.
20. The coordinates of 3 points are A(1, 1),B(-1, 4) and C(6, k). Find the value of k ifAB is perpendicular to BC.
Jawab:
[tex]gradientAB=-1:gradientBC[/tex]
[tex]\frac{yB-yA}{xB-xA} =-1:\frac{yC-yB}{xC-xB}[/tex]
[tex]\frac{yB-yA}{xB-xA} =-\frac{xC-xB}{yC-yB}[/tex]
[tex]\frac{4-1}{-1-1} =-\frac{6-(-1)}{k-4}[/tex]
[tex]\frac{3}{-2} =-\frac{7}{k-4}[/tex]
[tex]3(k-4)=-2(-7)[/tex]
[tex]3k-12=14[/tex]
[tex]k=8\frac{2}{3}[/tex]
Penjelasan dengan langkah-langkah:
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