what is the approximate size of Mr.Smith's class
1. what is the approximate size of Mr.Smith's class
Artinya ini " Berapa ukuran perkiraan kelas pak smith "
2. If p = 2 is a solution of the equation 2p - hp +6=0, find the value of h. Hence, find the other solution for the equation.
remember p = 2
Then,
2p² - hp + 6 = 0
2(2)² - h(2) + 6 = 0
2(4) - 2h + 6 = 0
8 + 6 - 2h = 0
14 - 2h = 0
2h = 14
h = 7
so, we have solution h is a 7
3. What is the solution of this problem?Please help me to solve this pattern answer? = ....
Terlihat polanya perkolom adalah:
- (hati x bulat) + trapesium
-(4 x 6 ) + 11 = -24 + 11 = -13
-(6 x 8) + 7 = -48 + 7 = -41
-(8 x 9) + 5 = -72 + 5 = -67
-(10 x 10) + 3 = -100 + 3 = -97
maka
-(2 x 4 ) + 13 = -8 + 13 = 5
4. an aqueous solution of sodium sulfate, naso, is electrolysed using carbon electrodes. what substance is formed at the cathode
Jawaban:
The substances formed at the cathode are hydrogen gas and hydroxide ions.
Tolong jadikan jawaban terbaik yaa, saling bantu
5. If sulphuric acid and sodium hydroxide solution are mixed, what is the result? Write your answer in the form of word equation
NaOH+H2SO4=>Na2SO4+H2O
setarakan
2NaOH+H2SO4=>Na2SO4+2H2O
6. What is the value of x from the equation -8x=-56
Penjelasan dengan langkah-langkah:
[tex] - 8x = - 56[/tex]
[tex]8x = 56[/tex]
[tex]x = \frac{56}{8} [/tex]
[tex]x = 7[/tex]
7. Water is added to 25.0 ml of a 0.866 m kno3 solution until the volume of the solution is exactly 500 ml. what is the concentration of the fi nal solution?
Jawaban:
Penjelasan:
[tex]M_{KNO_{3}}= 0,866 \ M = \frac{n}{V_{i}} \\\\V_{f}= 500 \ mL\\\\\delta V=25 \ mL\\\\V_{i}=V_{f}-\delta V\\\\V_{i}=500 \ mL-25 \ mL = 475 \ mL\\\\M_{f \ KNO_{3}}=M_{KNO_{3}}\times \frac{V_{i}}{V_{f}} =\\\\M_{f \ KNO_{3}}=0,866 \ M \times \frac{475 \ mL}{500 \ mL} =\\\\M_{f \ KNO_{3}}=0,866 \ M \times \frac{475 \ mL}{500 \ mL} = 0,8227 \ M[/tex]
8. A solution of H2SO4 with a molal concentration of 8.010 m has adensity of 1.354g/mL. What is the molar concentration of thissolution?
Answer with explanation:
You are given a solution of sulphuric acid with a molal concentration of 8.010 m and its density is 1.354 g/mL.
And we also know that the molar mass of sulphuric acid which is 98.079 g/mol.
◈ ◈ ◈
With the known datas, we work out the molar concentration in mol/L.
◈ ◈ ◈
The relation between molarity, molality and density is described within the following equation.
[tex]\frac{1}{m} = \frac{d}{M}-\frac{Mr}{1000}[/tex]
Where,
Density (d) = 1.354 g/mL
Molecular mass of solute (Mr) = 98.079 g/mol
Molality (m) = 8.010 m
Molarity (M) = ... mol/L
◈ ◈ ◈
So then,
[tex]\frac{1}{8.010\ m} = \frac{1.354\ g/mL}{M}-\frac{98.079\ g/mol}{1000}[/tex]
[tex]0.1248\ m = \frac{1.354\ g/mL}{M}-0.098079\ g/mol[/tex]
[tex]\frac{1.354\ g/mL}{M} = 0.098079\ g/mol+ 0.1248\ m[/tex]
[tex]\frac{1.354\ g/mL}{M} = 0.222879\ g/mmol[/tex]
[tex]M = \frac{1.354\ g/mL}{0.222879\ g/mmol}[/tex]
[tex]M = 6.075\ mol/L[/tex]
◈ ◈ ◈
Therefore, the molar concentration of said acid solution is 6.075 mol/L.
◈ ◈ ◈
~I hope this helps you~
9. Consider the linear equation xy + xy-4y=x² Let y be the general solution of the "reduced" (or complementary") equation xy + xy-4y = 0 and let y, be a particular solution of given differential equation. Show that y + y, is the general solution of DE
Bentuk faktorissasi prima dari FPB bilangan 24,42,dan 56 adalah
10. One solution of the quadratic equation x^2 + px + 12=0 is 3, then p=... and another solution is...
x² + px + 12 = 0
salah astu penyelesaian x = 3
maka
x² + px + 12 = 0
⇒ (3)² + p(3) + 12 = 0
⇒ 9 + 3p + 12 = 0
⇒ 3p = -21
⇒ p = -7
Sehingga
x² - 7x + 12 = 0
⇒ (x - 3)(x - 4) = 0
maka
x - 3 = 0 ⇒ x = 3
x - 4 = 0 ⇒ x = 4
Jadi, p = -7, dan penyelesaian yang satunya = 4
Terimakasih semoga membantu
11. determine the set of the solution of this linear equation 7x-y=2 and X+3y=16rumusnya apa ya?
Penjelasan dengan langkah-langkah:
brainly
Cari...
helloooo1
06.12.2016
Matematika
Sekolah Menengah Pertama
terjawab
Penyelesaian dari sistem persamaan 7x-y=2 dan x + 3y=16 adalah
1
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7x-y=2.............(x1) dikalikan 1 ......persamaan 1
x+3y=16..........(x7) dikalikan 7........ persamaan 2
jadi...
7x-y=2
7x+21y=112
yang sama dicoret yaitu 7x-7x=0
tinggal -y-(+21y)= -y-21y= -22y
trs 2-112= -110
jadi -22y : -110=
y =5
tinggal di masukin ke persamaan 2
x+3y=16
x+3(5)=16
x+15=16
x=16-15=1
x=1 di masukin ke persamaan 1
7x-y=2
7(1)-y= 2
7-y= 2
-y =2-7
-y= -5
y= 5
[tex]7x - y = 2 \\ - - - - - - \times 3 \\ \: \: \: 21x - 3y = \: \: 6 \\ \: \: \: \: \: \: \: \: x + 3y = 16 \\ - - - - - - - - + \\ \: \: \: 22x\: \: \: \: \: \: \: \: \: \: \: = 22 \\ \: \: \: \: \: x = \frac{22}{22} = 1 \\ \\ 7x - y = 2 \\ 7(1) - y = 2 \\ 7 - y = 2 \\ - y = 2 - 7 \\ - y = - 5 \\ y = \frac{ - 5}{ - 1} = 5 [/tex]
( x , y )
( 1 , 5 )
12. If, 18x = 36So, what is the solution of x²?
Jawab:
2
Penjelasan dengan langkah-langkah:
18x = 36
x=36/18
x=2
Answer :
[tex]18x = 36[/tex]
[tex]x = \frac{36}{18} [/tex]
[tex]x = 2[/tex]
So that,
[tex] {x}^{2} = {2}^{2} = 4[/tex]
13. What is the value of n in the equation 64 ÷ n = 8
Jawaban:
[tex]64 \div n = 8[/tex]
[tex] \frac{64}{n} = 8[/tex]
[tex]64 = 8n[/tex]
[tex]8n = 64[/tex]
[tex]8n \div 8 = 64 \div 8[/tex]
[tex]n = 8[/tex]
• • • • ───────────────────
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14. (i) If x = 5 is a solution of the equation x^2 - qx + 10 = 0, find the value of q.(ii )Hense, find the other solutions of the equation.(i) q =(ii) x =
Penjelasan dengan langkah-langkah:
x²-qx+10=0
5²-5q+10=0
25+10=5q
35 = 5q
q = 7
x²-7x+10 = (x-5)(x-2)
x=5 atau x=2
15. Integral 1/5x-6dx what is the answer of the equation?
Jawab:
[tex]\int\limits {\frac{1}{5}x - 6 } \, dx= \frac{x^2}{10} - 6x + C[/tex]
Penjelasan dengan langkah-langkah:
[tex]\int\limits {\frac{1}{5}x - 6 } \, dx = ....\\[/tex]
Rumus integral :
[tex]\int\limits{ax^n} \, dx = \frac{ax^{n-1}}{n-1} + C[/tex]
Maka :
[tex]\int\limits {\frac{1}{5}x - 6 } \, dx = \frac{1/5}{1+1}x^{1+1} - 6x + C\\= \frac{x^2}{10} - 6x + C[/tex]
16. What is the equation of axis of symmetry of the given quadratic equation? * y = x2 – 8x - 9
Jawaban:
x = 4
Penjelasan dengan langkah-langkah:
x = -b/2a
= -(-8)/2(1)
= 4
Jawaban:
x = 4
Penjelasan dengan langkah-langkah:
semoga membantu:)
17. What is the molarity of a solution containing 4 moles of KCl in 2.5 L of solution?
Penjelasan:
dik : n KCl = 4 mol
v = 2,5 L
dit : M = ?
jb :
M = n / v
= 4 mol / 2,5 L
= 1,6 mol/L
semoga membantu :)
18. What is the solution of 2³×3⁴÷6²
Jawaban:
the solution of your problem
Penyelesaian dari 2³ x 3⁴ : 6² adalah 18.
PembahasanPada bentuk perpangkatan, apabila dalam operasi perkalian dan pembagian terdapat bilangan pokok yang berbeda, maka harus dihitung dahulu masing-masing. Dalam arti, dahulukan perpangkatan, baru selesaikan operasi lainnya.
Dalam hal ini perlu diingat singkatan PaKBaTaK, yaitu pangkat, kali, bagi, tambah, kurang. Artinya perpangkatan didahulukan, diikuti perkalian dan pembagian, selanjutnya penjumlahan dan pengurangan.
Apabila dalam suatu operasi tanpatandakurungmelibatkan perkalian dan pembagian, hitung dari sebelah kiri lalu ke kanan. Begitupun untuk suatu operasi yang melibatkan penjumlahan dan pengurangan.
Lain halnya apabila terdapat tandakurung. Maka operasi di dalam tanda kurung didahulukan.
↓↓↓
Penyelesaian:
2³ x 3⁴ : 6² = 8 x 81 : 36
= 648 : 36
= 18
Jadihasildarioperasiperpangkatantersebut adalah18.
_______________________
Detail JawabanMapel:Matematika
Kelas:X
Materi:Bab 1.1 - Bentuk Akar, Eksponen, Logaritma
KataKunci:Pangkat, Bilangan Pokok, Eksponen
KodeSoal:2
KodeKategorisasi:10.2.1.1
19. What is the solution of 9log2+4log2-18log2=
[tex]
9 \: log \: 2 + 4 \: log \: 2 - 18 \: log \: 2 \\ \\ = (9 + 4 - 18) \: log \: 2 \\ \\ = - 5 \: log \: 2[/tex]
20. what is the solution of pollution problem?pls help me
Jawaban:
reduce the use of motorized vehicles,no smoking,and use public transportation
The solution to polution problems is to reduce the use of vehicles, by using public transportations insteadPlant more tress with the saying “cut one tree. Plant ten trees” Trees take long time to grow, so we should plant more than how much we chop down
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