hasil dari 104 : (-8) - (-5) × 12 adalah
1. hasil dari 104 : (-8) - (-5) × 12 adalah
104:(-8)=-13x12=-156-(-5)=-151
karenayangdikerjakanterlebihdahulu:laluxlalu+lalu-
maafklosalah
semogabermanfaat:)
2. Hasil dari 104:(-8)-(-5)×12
Jawaban:
-73
Penjelasan dengan langkah-langkah:
:104:(-8)-(-5)×12kita mulai perkalian dan pembagian terlebih dahulu:-13-(-60): -73Jawaban:
hasil dari 104:(-8)-(-5)×12=47
Penjelasan dengan langkah-langkah:
Semoga membantu
semoga bermanfaat
Kalau bisa jadikan jawaban tercerdas ya ^_^
Jangan lupa lihat gambarnya juga ya >_<
Saya pasti bener kok !!
Jangan lupa kasih jawaban tercerdas ke saya ya :)
3. a triangle has base length of (x-2) cm and high of 8 cm. if its area is 104 cm, then hypotenuse is...
Alas = x-2
Tinggi = 8
Luas = 104
Maka,
1/2 at = 104
1/2 (x-2)8 = 104
4(x-2) = 104
x-2 = 26
x = 28
Didapat:
a = 26
t = 8
Sehingga,
Sisi miring:
= √26² + 8² = √676 + 64
= √840
= 2√210 cm
4. 104×12= Tolong jawab kebawah ya
104
12
_____×
208
104•
_____×
1248
#samasamabelajar
#jadikanjawabantercerdas
5. An object with a mass of 200 g has a heat capacity of 104 J/oC. The specific heat of the substance is.
An object with a mass of 200 g has a heat capacity of 104 J/°C. The specific heat of the substance is 20.8 J/kg°C
Solution:
Known:
m = 200 gram = 0,2 kg
C = 104 J/°C
Asked:
c = ...?
Answer:
c = m × c
= 0,2 × 104
= 20.8 J/kg°C
So, the specific heat of the substance is 20.8 J/kg°C.
6. [2,4 x 10-²] x [5 x 10^6] =.... a. 1,2 x 104b. 12 x 104c. 12 x 105d. 1,2 x 105
Jawaban:
Disamakan sukunya dulu lalu jangan lupa difaktorkan seperti di foto
7. porogapit 104:5 adalah
Jawaban:
104÷5=2,8Penjelasan dengan langkah-langkah:
bilangan 5 dikalikan 10, hasilnya adalah 2 dan diletakkan diatas. lalu hasil dari pembagian 10÷5 diletakkan di bawah angka 10. nah 4 kan tidak bisa dibagi 5, maka turunkan angka nol, lalu beri tanda koma di belakang angka 2. lalu bilangan 4 jadinya angka 40 bukan 4 lagi karena sudah diberi 0 dan jumlahkan 40÷5, maka hasilnya 8
terima kasihsemoga jawaban ini membantu8. 19⁴ - 12² = ? 104² = ?
Jawaban~
1.) 130.177
2.) 10.816
_____________________1.)19^4 - 12^2
=> 19^4 - 12^2
=> ( 19 × 19 × 19 × 19 ) - ( 12 × 12 )
=> 130.321 - 144
=> 130.177
2.)104^2
=> 104^2
=> ( 104 × 104 )
=> 10.816
...•...•...•...•...•...•...•...•...•...•...•
#CMIIW
Jawab:
Penjelasan dengan langkah-langkah:
19⁴ - 12² = (19*19*19*19) - (12*!2) = 130.321 - 144 = 130.177
104² = (104*104) = 10.816
9. berapa jumlah dari 4+8+12+16+..+104
Jawaban:
Sn=n/2(2a+(n-1)b)
UN=a+(n-1)b
pertama mari kita cari Un
Un=4+(n-1)4=104
=4+4n-4=104
=4n=104
=n=26
S26=26/2(2(4)+(26-1) 4)
S26=13(8+100)
=13(108)
=1404
Penjelasan dengan langkah-langkah:
Semoga membantu dan jangan lupa jadikan jawaban tercerdas karena aku udah capek nulisnya
Jawab:
Penjelasan dengan langkah-langkah:
Pake sifat batisan aritmatika bisa
4+8+12+16+.....+104
a=4
b=8-4=4
Un=a+(n-1)b
104 =4+(n-1)4
104=4+4n-4
104=4n
n=104/4
n=26
Ada 26 suku
S26 = 26/2 ( 2a+(n-1)b)
=13(2.4+25.4)
=13(8+100)
=14(108)
=1512
10. Exercise:1.How much heat is required to melt 10 kg of alcohol in solid? The heat of fusion ofalcohol is 6,9 x 104 J kg-1.2.How much heat is required to vaporize 5 kg of water? The heat of vaporization of wateris 2,27 3 106 J kg-1.
Jawaban:
1. 690000 joule = 690 kj
2. 11365 kj
Penjelasan:
1. diket : m = 10 kg
U = 6,9 x 10 pngkt 4 joule/ kg
jawab : Q = m x U = 10 kg x 69000 j/kg
= 690000 joule
2. diket : m = 5 kg
U = 2.273.000 j/ kg
jawab : Q = m x U = 5 kg x 2.273.000 j/kg
= 11.365.000 joule
11. An object with a mass of 200 g has a heat capacity of 104 J/oC. The specific heat of the substance is
An object with a mass of 200 g has a heat capacity of 104 J/°C. The specific heat of the substance is 20.8J/kg°C
Solution:Known:
m = 200 gram = 0,2 kg
C = 104 J/°C
Asked:
c = ...?
Answer:
c = m × c
= 0,2 × 104
= 20.8J/kg°C
So, the specific heat of the substance is 20.8 J/kg°C.
12. keliling sebuah belah ketupat 104 cm. jika perbandingan panjang diagonal 5:12,maka luas belah ketupat tersebut adalah
104 ÷ 4 = 26
menggunakan triple phytagoras
= 5,12,13
26 ÷ 13 = 2
berarti triple phytagoras dikali 2
= 5 × 2 = 10 cm × 2 = 20 cm
12 × 2 = 24 cm × 2 = 48
( dikalikan 2 karena diagonal )
13 × 2 = 26 cm ( hipotenusa )
ditanya luas belah ketupat = d1 × d2 / 2
= 20 × 48 / 2 = 480 cm²K = 4 × r
104 = 4r
r = 104 : 4
r = 26
karena panjang diagonal disebut 5:12 maka dimisalkan menjadi 5x:12x
jumlahkan nilai x dari perbandingan panjang diagonal dibagi 2 dan panjang rusuk menggunakan phytagoras
r^2 = (2,5x)^2 + (6x)^2
26^2 = 6,25x^2 + 36x^2
676 = 42,25x^2
x^2 = 676 : 42,25
x^2 = 16
x = 4
hitung diagonal 1 dan 2
5x = 5 × 4 = 20
12x = 12 × 4 = 48
hitung luas belah ketupat
L = (d1 × d2) : 2
= (20 × 48) : 2
= 960 : 2
= 480 cm^2
mohon maaf kalau keliru. semoga beemanfaat
13. Helen and Ivan had the same number of coins. Helen had a number of 50-cent coins and 64 20-cent coins. These coins had a mass of 1.134kg. Ivan had a number of 50-cents coins and 104 20-cent coins. A) given that each 50-cent coin is 2.7g more heavier than a 20-cent coin, what is the mass of Ivan's coin in kg?
Jawab:
1.026 kgPenjelasan dengan langkah-langkah:
Let n be the number of Helen's 50-cent coins.
It is given that:
Helen and Ivan had the same number of coinsHelen had a number of 50-cent coins and 64 20-cent coinsIvan had a number of 50-cents coins and 104 20-cent coins104 – 64 = 40
From these facts, we know that Ivan had 40 20-cent coins more than Helen's. Therefore, we can get that the number of Ivan's 50-cent coins which equals to:
n – 40
Let x be the mass of each 50-cent coin, and y be the mass of each 20-cent coin.
At Helen's side, we can get that
nx + 64y = 1.134kg = (1.134 * 1000) g
⇔ nx + 64y = 1,134 .....(i) (in grams)
Given that each 50-cent coin is 2.7g heavier than a 20-cent coin, we can get that
x = y + 2.7 (in grams)
Substitute x to equation (i):
n(y + 2.7) + 64y = 1,134 .....(ii)
Let m be the mass of Ivan's coins, we can get that:
(n – 40)x + 104y = m
⇔ nx – 40x + 104y = m
Then we substitute x with y + 2.7.
⇔ n(y + 2.7) – 40(y + 2.7) + 104y = m
⇔ n(y + 2.7) – 40y – 40(2.7) + 104y = m
⇔ n(y + 2.7) + 64y – 108 = m
Substitute n(y + 2.7) + 64y with 1,134 we got in equation (ii):
⇔ 1,134 – 108 = m
⇔ m = 1,026 g = (1,026 / 1,000) kg
⇔ m = 1.026 kg
CONCLUSION:
∴ The mass of Ivan's coins is 1.026 kg.14. Titik-titik stasioner dari grafik fungsi f(x) = x³ + 6x² – 15x + 4 adalah...A. (1,76) dan (4, 104)B. (-1, 12) dan (4, 104)C. (-5, 104) dan (1,-4)D. (-5, 104) dan (1,4)E. (-1, 24) dan (5, 204)
Jawab:
d. (-5,104) dan (1,4)
Penjelasan dengan langkah-langkah:
Titik stationer
Syarat : f'(x) = 0
f(x) = x³ + 6x² – 15x + 4
f'(x) = 0
3x² + 12x - 15 = 0
x² + 4x - 5 = 0
(x - 1)(x + 5) = 0
x = 1 atau x = -5
x = 1 → f(1) = 1³ + 6.1² - 15.1 + 4 = -4
x = -5 → f(-5) = (-5)³ + 6(-5)² - 15(-5) + 4 = 104
Titik stationer
(1,-4) dan (-5,104)
Jawab:
Penjelasan dengan langkah-langkah:
turunan
titik titik stationer
_
soal
f(x) = x³ + 6x² – 15x + 4
f'(x= 0
3x² + 12x - 15 =0
3(x² + 4x - 5) =0
3(x + 5)(x - 1) =0
x= - 5 atau x = 1
titk stationer { x,f(x)}
x= - 5 , f(-5) = 104
x= 1 , f(1)= - 4
titik stationer = (-5, 104), (1 , - 4)
15. Methanol (CH3OH), also called methyl alcohol, is the simplest alcohol. It is used as a fuel in race cars and is a potential replacement for gasoline. Methanol can be manufactured by combination of gaseous carbon monoxide and hydrogen. Suppose 68,5 kg CO(g) is reacted with 8,60 kg H2 (g). Calculate the theoretical yield of methanol. If 3,57 x 104 g CH3OH is actually produced, what is the percent yield of methanol?
Theoritical yield of [tex]CH_{3}OH[/tex] = 68,8 kg.
actual yield [tex]CH_{3}OH[/tex] = 35,7 kg
% yield of [tex]CH_{3}OH[/tex] = [tex]\frac{35,7}{68,8}[/tex] ×100% = 51,88% = 52%
Penjelasan:
Diketahui :
mass CO = 68,5 kg (Mr = 28) ⇒ mol CO = 2,4kmol
mass [tex]H_{2}[/tex] = 8,6 kg (Mr = 2) ⇒ mol [tex]H_{2}[/tex] = 4,3 kmol
Chemical Equation:
CO + 2 [tex]H_{2}[/tex] → [tex]CH_{3}OH[/tex]
mol mula: 2,4 4,3
mol bereaksi: 2,15 4,3 2,15
___________________________
mol sisa : 0,25 - 2,15
mol [tex]CH_{3}OH[/tex] = 2,15
Mr [tex]CH_{3}OH[/tex] = 32
mass [tex]CH_{3}OH[/tex] = 2,15 × 32 = 68,8 kg
Theoritical yield of [tex]CH_{3}OH[/tex] = 68,8 kg.
actual yield [tex]CH_{3}OH[/tex] = 35,7 kg
% yield of [tex]CH_{3}OH[/tex] = [tex]\frac{35,7}{68,8}[/tex] ×100% = 51,88% = 52%
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https://brainly.co.id/tugas/2430668
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16. 4 + 8 + 12 + ... + 104 = ....
Jawab:
1404
Penjelasan dengan langkah-langkah:
(4+104)+(8+100)+(12+96)+....+(52+56)
= 108+108+...+108
= 108 x 13
= 1404
17. change these sentences into positive , negative, or interrogative (+) Yudi is a student of mts 104 (-) ... (?) .... (+) .... (-) you are not a teacher
Jawaban:
(-) Yudi is not a student of mts 104.
(?) Is Yudi a student of mts 104?
(+) You are a teacher.
Maaf kalau salah
1. (+) yudi is a student of mts 104(-) yudi is not a student of mts 104
(?) is Yudi a student of mts 104?
2. (+) you are a teacher
(-) you are not a teacher
(?) are you a teacher?
Semoga membantu
Semangat teruss belajarnyaaa
18. An object with a mass of 200 g has a heat capacity of 104 J/oC. The specific heat of the substance is
Jawaban:
520 J/Kg C
diketahui :
m = 200 = 0,2
C = 104 J/C
ditanya :
c = ?
dijawab :
c = C/m
c = 104/0,2
c = 520 J/Kg C
19. Hasil dari 〖(-5)〗^3+〖(-5)〗^2+〖(-5)〗^1+〖(-5)〗^0 adalah ... 100 -100 104 -104
Jawaban:
Jadi, jawabannya adalah -100
20. An object with a mass of 200 g has a heat capacity of 104 J/oC. The specific heat of the substance is
Jawaban:
520 J/Kg C
Penjelasan:
diketahui :
m = 200 = 0,2
C = 104 j/kg C
ditanya :
c = ..... ?
dijawab :
c = C/m
= 104/0,2
= 520 j/kg C
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