An arrow with a mass of 20 grams is launched from a bow at a speed of 60 m/s. Calculate the amount of chemical energy required to draw the bowstring.
1. An arrow with a mass of 20 grams is launched from a bow at a speed of 60 m/s. Calculate the amount of chemical energy required to draw the bowstring.
Jawaban:
36 Joule
Penjelasan:
Diketahui :
m = 20 gr = 0,02 kg
v = 60 m/s
Ditanyakan :
EK ... ?
Jawab :
EK = 1/2 m v^2
EK = 1/2 0,02 (60^2)
EK = 1/2 0,02 (3600)
EK = 36 Joule
SolutionKnown :
m = 20 gr = 0,02 kg
v = 60 m/s
[tex] \\ [/tex]
Asked :
E[tex] \sf {_{k}} [/tex] = ... ?
[tex] \\ [/tex]
Answer :
E[tex] \sf {_{k}} [/tex] = [tex] \sf \dfrac{1}{2} [/tex] · m · v²
[tex] \: \: \: \: \: [/tex] = [tex] \sf \dfrac{1}{2} [/tex] × 0,02 × 60²
[tex] \: \: \: \: \: [/tex] = 36 Joule
So, the amount of kinetic energy needed to pull the bowstring is 36Joule.
[tex] \\ [/tex]
──────────────────────────
[tex] \\ [/tex]
PenyelesaianDiketahui:
m = 20 gr = 0,02 kg
v = 60 m/s
[tex] \\ [/tex]
Ditanya:
E[tex] \sf {_{k}} [/tex] = ... ?
[tex] \\ [/tex]
Jawab:
E[tex] \sf {_{k}} [/tex] = [tex] \sf \dfrac{1}{2} [/tex] · m · v²
[tex] \: \: \: \: \: [/tex] = [tex] \sf \dfrac{1}{2} [/tex] × 0,02 × 60²
[tex] \: \: \: \: \: [/tex] = 36 Joule
Jadi, energi kinetik yang diperlukan untuk menarik tali busur adalah 36Joule.
2. A small bag 0.3 kg is thrown horizontally with a constant speed of 10m/s. the ball hits the wal and reflected with the same speed. what is the change in the mommentum of the ball?
Jawaban:
nggak bisa bahasa Inggris
Penjelasan:
tanya Google sudah belum
3. A box of mas 2 kg was released from a helicopter flying horizontally at a speed og 20m/s. find the kinetic energy of the box after 6,5 seconds?
mass = 2 kg
velocity = 20 m/s
time = 6,5 seconds
kinetic energy = ?
kinetic energy = 1/2.m.v^2
kinetic energy = 1/2.2.20^2
kinetic energy = 400 J
kinetic energy after 6,5 seconds :
400 J. 6,5 seconds = 2600 Joule
Answer : 2600 Joule
4. The speed of a shot put ball at the bottom of an inclined plane with a mass of m and radius of R rolling without a slip down the inclined plane at a height of h is......
ROTATION of RIGID BIDIES
• solid ball
• H
• g
speed at bottom
v = √((10/7) g h)
v = √((10/7) g H)
5. .the distance between pontianak and singkawang 150 km.A bus running at the speed 50 km/hour.it left the pontianak at 08.00O’clock. What time will the bus reach the singkawang? 2. yesterday,rom drove his car at an average speed of 50 km/h for 2 hours 30 minutes.how did he travelled? 3. A plans cover a distance of 2100 miles at a speed of 700 mph. How long will it take to complete this journey? 4.A truck driver travels for 4 hours and 30 minutes at a constant speed and travels 252 kilometres.what is the speed of the trucks in kilometer per hour ?
Penjelasan dengan langkah-langkah:
1weu idk sydyxgshdjdif
Semoga terbantu. Maaf kalau ada yg salah6. Suresh drives his car to a place 150 km away at an average speed of 50 km/hr and returns at 30 km/hr. What is his average speed for the whole journey in km/hr?
Suresh drives his car to a place 150 km away at an average speed of 50 km/hr and returns at 30 km/hr. What is his average speed for the whole journey in km/hr?
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Translate :
Suresh mengendarai mobilnya ke tempat yang berjarak 150 km dengan kecepatan rata-rata 50 km / jam dan kembali pada 30 km / jam. Berapa kecepatan rata-rata untuk seluruh perjalanan dalam km / jam?
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[tex]\boxed{\boxed{\tt{s = v \times t}}}[/tex]
s = distance (km)
v = speed/velocity (km/hr)
t = time (hr)
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Known:
[tex]\tt{s_{1} = 150} \\ \tt{s_{2} = 150} \\ \tt{v_{1} = 50 \: km/hr} \\ \tt{v_{2} = 30 \: km/hr}[/tex]
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Asked:
[tex]\tt{\tt{ \bar{x_{v}}} = ... ?}[/tex]
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Answered:
Sum of distance
[tex]\tt{\Sigma s = s_{1} + s_{2}} \\ \tt{ \: \: \: \: \: \: = 150 + 150} \\ \tt{ \: \: \: \: \: \: = 300 \: km}[/tex]
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[tex]\tt{t_{1} = \dfrac{s_{1}}{v_{1}}} \\ \tt{ \: \: \: \: \: = \dfrac{150}{50}} \\ \tt{ \: \: \: \: \: = 3 \: hr}[/tex]
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[tex]\tt{t_{2} = \dfrac{s_{2}}{v_{2}}} \\ \tt{ \: \: \: \: \: = \dfrac{150}{30}} \\ \tt{ \: \: \: \: \: = 5 \: hr}[/tex]
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Sum of time
[tex]\tt{\Sigma t = t_{1} + t_{2}} \\ \tt{ \: \: \: \: \: \: = 3 + 5} \\ \tt{ \: \: \: \: \: \: = 8 \: hr}[/tex]
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[tex]\tt{ \bar{x_{v}} = \dfrac{\Sigma s}{\Sigma t}} \\ \tt{ \: \: \: \: \: = \dfrac{300}{8}} \\ \bold{ \: \: \: \: \: = 37,5 \: km/hr}[/tex]
7. A speed-time graph shows that a car moves at 10 m/s for 10 s. The car's speed then steadily decreases until it comes to a stop at 30 s. The types of the motion (Jenis geraknya) which describes the slope of the speed-time graph from 10 s to 30 s is called
Jawaban:
Grafik kecepatan-waktu menunjukkan bahwa sebuah mobil bergerak dengan kecepatan 10 m/s selama 10 s. Kecepatan mobil kemudian mantap
berkurang sampai berhenti pada 30 s.
Jenis-jenis gerak (Jenis geraknya) yang menggambarkan kemiringan grafik kecepatan-waktu dari 10 s ke 30 s adalah
ditelepon dari grafik kecepatan-waktu dari 10 s ke 30 s adalah
ditelepon
Penjelasan:
MAAF KALOSALAH
8. A stone is thrown horizontally from the top of a vertical cliff and lands 4.0s later at a distance 12.0m from the base of the cliff. Ignore air resistance. a. Calculate the horizontal speed of the stoneb. Calculate the height of the cliffjawab pakai rumus dan cara yaaa!!
Jawaban:
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9. A turtle swam 720 metres at a speed of 180 metres per minute. Then, it swam another 960 metres at a speed of 160 metres per minute. What was the turtle's average swimming speed?
Penjelasan dengan langkah-langkah:
720/180= 4 minutes
960/160= 6 minutes
the turtle swam for (720 + 960=) 1680 metres in (4 + 6 =) 10 minutes.
it means it average speed is...
1680/10
= 168metres/minute
10. The motorcycle moves on the straight road at a speed of 72km/h. In SI unit, the speed of the motorcycle is
Jawaban:
72km = 72000 m
1 hr = 3600 s
72000m/3600s = 20m/s
11. How would you describe the horizontal motion of a projectile launched at an angle?A. It has a uniform horizontal aceelerationB. It has a varying horizontal velocityC. It has a constant horizontal accelerationD. It has a uniform velocity-With explanation-
Jawaban:
A.memiliki percepatan horizontal beragam
A. It has a uniform horizontal aceeleration
12. A boy that has mass 40kg runs at speed 5m/s. The kinetic energy of a boy is
◾ Materi : Usaha dan Energi
◾ Sub materi : Energi
◾ Mapel : Fisika
◾ Kelas : VIII SMP (KTSP)
◾ Keyword : Energi Kinetik
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Diketahui :
m = 40 kg
V = 5 m/s
Ditanya :
Ek = ?
Penyelesaian :
Energi kinetik merupakan energi yang dimiliki oleh suatu benda karena kecepatannya.
Gunakan rumus energi kinetik :
[tex]\boxed{ Ek = 1/2mV^{2}} [/tex]
Ek = 1/2mV²
Ek = 1/2 x 40 x 5²
Ek = 20 x 25
Ek = 500 Joule
-> Jadi, energi kinetik dari anak tersebut adalah 500 J
semoga membantu
# sharing is caring #
-vin
Rumus : Ek = 1/2. m.v2
Ek =
[tex] \frac{1}{2} .40. {5}^{2} \\ = 20.25 \\ = 500 \: m {s}^{ - 2} [/tex]
13. How far will a bus travel in 30 s at a speed of 15 m/s?
Jawaban:
450 m
Penjelasan:
Diketahui:
v : 15 m/s
t : 30 s
Ditanya:
s?
Jawab:
s = v × t = 15 m/s × 30 s = 450 m
14. A bullet of mass 0.20 kg travels horizontally at a speed of 400 m/s. it strikes a stationary wooden block of mass 1.80 kg resting on a frictionless, horizontal surface. the bullet stays in the block. what is the speed of the bullet and the block immediately after the impact? 200 m/s 80 m/s 44 m/s 40 m/s (in ulanganku hari ini)
Jawaban:
40 m/s
Penjelasan:
Known :
Mb = 0.20 kg
Vb = 400 m/s
Mw = 1.8 kg
Vw = 0 m/s (Resting)
Solution :
Because bullet stays in the block, then the speed of the bullet and the block will be same :
Mb . Vb + Mw . Vw = (Mb + Mw) . V
0.2 . 400 + 0 = (0.2 + 1.8) . V
V = 40 m/s
15. How would you describe the horizontal motion of a projectile launched at an angle?A. It has a uniform horizontal aceelerationB. It has a varying horizontal velocityC. It has a constant horizontal accelerationD. It has a uniform velocityWITH EXPLANATION!
Jawaban:
Bagaimana Anda menggambarkan gerakan horizontal proyektil yang diluncurkan pada suatu sudut?
A. Memiliki percepatan horizontal yang seragam
B. Memiliki kecepatan horizontal yang bervariasi
C. Ini memiliki percepatan horizontal yang konstan
D. Ini memiliki kecepatan yang seragam
DENGAN PENJELASAN!
Soalx :How would you describe the horizontal morion of a projectile laundched at an angle??
Jawaban :C. It has a constant horizontal acceleration
Penjelasan:
Horizontal memiliki makna terletak pada garis atau bidang yang sejajar dengan horinzon atau garis datar : mendatar
Semoga membantuANSWER BY : Naysa#NoCopas#NoErorr#NoNyontex#Siapa yang menghapus jawaban ku berarti dia berdosa16. A boat whose speed is 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream is ___ km/hr. tolong jawab!
Jawaban:
tuhhhhh yaaaa jawabanya
beri❤❤
Jawaban:
Speed of the boat = 15 km/hour
Water goes 30 km downstream
Total time = 4 hours 30 minutes
The Speed of the Stream = 5 km/hour
Semoga Bermanfaat :)
#BelajarBersamaBRAINLY
17. The Antasena bus is traveling at a speed of 60 km/hour. Bima Bustraveling at a speed of 20 m/s. Which bus goesfaster? explain with answer!
Jawab:
Bima Bus is faster @ 20 m/s
Penjelasan:
Antasena Bus..
60 km = 60,000 m
1 hr = 3,600 s
____________
Antasena Bus =
60,000 m/3,600 s =
50/3 m/s ≈
Antasena Bus ≈ 16.67 m/s
_______________
Bima Bus = 20 m/s
Bima Bus is faster
(xcvi)
Antasena Bus = 60 km/ hour.
Bima Bus = 20 m/s
• Antasena Bus
60 km = 60 × 1.000 = 60.000 m
[tex] = \frac{60.000 \: m}{3.600 \: s} [/tex]
= 16,67 m/s
• Bima Bus
= 20 m/s
So,
Antasena Bus < Bima Bus
= 16,67 m/s < 20 m/s
BimaBusGoesthefaster.
↓Answer Of Core ↓So, The answer's correct is BimaBusGoesThefaster.→HopeThisHelp←18. David ran one round around the field at a speed of 6m/s. Then he ran one more round at a speed of 4m/s. What was the average speed of David?
Jawaban:
average speed of David is 5m/s
19. a 300 kg car rolls up and down a street. It passed at top of hill A, whuch 50m high at speed of 8m/s. How fast is the car going to next hill (B) which high is 30 m?
240?
Maaf klo salah ya.. Tapi soalnya lupa rumusnya
20. A half metre rule AB is freely pivoted at 18cm from end A and balances horizontally when a body of mass 35g is hung 48cm from end B.Calculate the mass of the rule
sikap kayang Berdasarkan pernyataan tersebut melakukan gerak
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