5/9 of a piece of metal has a mass of 7 kg. What is the mass of 2/7 of the piece of metal?
1. 5/9 of a piece of metal has a mass of 7 kg. What is the mass of 2/7 of the piece of metal?
Jawaban:
5/9 sepotong logam memiliki massa 7 kg. Berapa massa 2/7 dari potongan logam?
Penjelasan dengan langkah-langkah:
maap banget klo salah atau gx tepat.
2. An empty box has a mass of 46 grams. Jims packs 20 cans of soup into the box. Each can of soup has a mass of 450 grams. What is the total mass of the box of soup?
Jawab:
946 g
Penjelasan dengan langkah-langkah:
Diketahui :
[tex]m^{box}[/tex] : 46 g
can/box : 20
[tex]m^{can}[/tex] : 450
Ditanya :
[tex]m^{box of soup}[/tex] : ?
Jawab :
[tex]m^{box of soup}[/tex] = [tex]m^{box}[/tex] + n([tex]m^{can}[/tex])
= 46 g + 20(450 g)
= 46 g + 900 g
= 946 g
Jadi :
total mass of the box of soup is : 946 grams/0,946 kg
Sorry if im wrong :)
3. I - get - not - will - piece - of - a - paper. Make it a good sentence! *I will not get a piece of paperI will get not piece of a paperI piece not will get of a paperI not of a piece will get paperI get a will not piece of paper
Jawaban:
I will not get a piece of paper
=Saya tidak akan mendapatkan selembar kertas
Jawaban:
I will not get a piece of paper.
(Aku tidak akan mendapatkan selembar kertas.)
Penjelasan:
Ini simple future tense kalimat negatif ya.
Rumusnya
(+) S + Will + V1
(-) S + Will + not + V1
(I + Will + not + get + a piece of paper.)
(?) Will + S + V1 + ...?
4. known mass of 10 L. of nitrogen gas is 5 grams.at a certain temperature and pressure (T,P) calculate the relative atomic mass(Ar) of 20 L. AO2,which has a mass of 44 grams of gas?
Greetings Panji,
We’re going to utilize the Avogadro constant. P.V = n.R.T , since it was known that the temperature and pressure are at a certain level , assume as identical. Therefore we can cross out P, T, and R too because (R is a constant of 0.082), from this elimination we got the rule of Avogadro where we could compare volume and moles (gr/mr). A simple math will reveal that the second gas has 5/14 moles. We can break open the moles formula by dividing mass and the relative atomic mass.
There u go :D
5. "look at the picture below. Jamie has a square piece of paper. Each side of the square is 37 mm.What is the perimeter of the piece of paper?" tolong di jawab ya kak,makasih❤
Jawab:
1369
Penjelasan dengan langkah-langkah:
1 sheet of paper because,
square formula is= s²
so, 37 x 37 = 1369
Maaf klo salah yah..
(" jamie has a..." greget saya namanya tinggal tambahin huruf "n")
6. the mass of pencil 115 grams the mass of a book is 385 grams what is the their total mass
Jawaban:
500 mass is the total mass
The total mass is115 grams + 385 grams=500 grams
So,the total mass is 500 grams
7. 14. a book - a piece of papera. A book is thick than a piece of paperb. A book is thiner than a piece of paperC. A book is more thick than a piece of paperd. A Piece of paper is thic Jer than a bookbantu jawab agy, boleh?
Jawaban:
Jawabannya A.a book is Thick than a piece of paper
Penjelasan:
semoga membantu :)
8. An object has a mass of 10 grams and volume of 2mL. What is the density of the object
Jawaban:
ro(density)=m:v
10:2=5
Penjelasan:
9. Kumar wishes to cut the biggest possible number of squares from a rectangular piece of paper without any leftover paper. The piece of paper has a length of 65cm and breath of 50cm. 1)What is the length of each square? 2) How many squares can he cut altogether?
HCF
[tex]65 |50 \\ 5 - - - - \\ 13 |10 \\ \\ 1).the \: length \\ 5 \: cm \\ \\ 2).13 \times 10 \\ 130 \: squares[/tex]
10. The weight of a piece of wire is directly proportional to its length. A piece of wire is 25 cm long and has a weight of 6 grams. What is the weight of another piece of the same wire which is 30 cm long.
step-by-step explanation :
According to the question
25 cm piece of wire has weight of 6 grams
So, 1 cm of wire will has a weight of 0.24 grams
( as 25cm weight = 6grams,
1cm = 6/25 grams = 0.24 grams)
As 1 cm = 0.24 grams so,
30 cm = 0.24 x 30 grams
= 7.2 grams
11. you-do-need-piece-a-paper- of =
Jawaban:
do you need a piece of paper?
12. 1. A bag of grapes has a mass of 4.55 kg. A bag of mangoes has a mass of 6.90 kg. What is the total mass of the two bags of fruits? *
Jawaban:
4.55 + 6.90 = 11.45
Penjelasan:
sorry if it's wrong, hope it helps^^
Jawaban:
4,55 + 6,90 = 11,45
Penjelasan:
total mass of the two bags of fruits is 11,45 kg
13. Why are you holding a piece of paper
Jawaban:
Mengapa kamu memegang selembar kertas?
14. THE TOTAL MASS OF MACHINE A AND MACHINE B IS 80.5 KG. THE MASS OF MACHINE B IS 4 TIMES THE MASS OF MACHINE A. WHAT IS THE MASS OF MACHINE B? EXPRESS YOUR ANSWER IN GRAMS!
A + B = 80,5
A + 4A = 80,5
5A = 80,5
A = 80,5 : 5 = 16,1
B = 4A = 4(16,1) = 64,4 KG = 64.400 GR
15. A bag of grapes has a mass of 4.55 kg. A bag of mangoes has a mass of16.90 kg. What is the total mass of the two bags of fruits?
Jawaban:
total mass = grapes mass + mangoes mass
total mass = 4.55 kg + 6.90 kg
total mass = 11.45 kg
16. arti dari a piece of paper
Artinya adalah Selembar Kertas
A piece of paper ,, artinya selembar kertas .
17. The mass of a sack of potatoes is 5 kilograms 305 grams. What is the mass of the sack of potatoes in grams?
Jawaban:
jika Anda ingin bertanya itu deng 234
18. liquid x has a mass of 9.8 grams and volume of 1.4 centimeter cubed what si the density of liquid x
Jawaban:
0.0001428571428
Penjelasan:
Density
9.8 g = 9.8 / 1000 = 0.0098 Kg
1.4 cm^3 = 1.4 / 1000000 = 0.0000014 m^3
ρ = m/V
= 0.0000014/0.009.8
= 0.0001428571428
#backtoschool2019
19. artinya l need a piece of paper
Jawaban:
aku butuh selembar kertas
Penjelasan dengan langkah-langkah:
maaf kalau salah
I need a piece of paper : Saya butuh selembar kertas.
Tolongdilovedanjanganlupaberikanjawabantercerdasya^•^
20. A Box with 4 simiral books has a mass of 6.26kg. The mass of the box is 0.5 kg. Find the mass of one book and express your answer in kilograms and grams. HELP
Jawab:
1.44 kg = 1440 grams
Penjelasan dengan langkah-langkah:
The mass of 4 similar books = 6.26 kg - 0.5 kg = 5.76 kg.
The mass of each book = 5.76 kg : 4 = 1.44 kg = 1440 grams
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