Find the real roots of the equation. X²-2x+5=0
1. Find the real roots of the equation. X²-2x+5=0
There is no real roots in this equationd
Why?
Because D=b^2-4ac=4-20=-16<0tidak ada akar akar yang real karena Diskriminan <0
b2-4ac = (-2)2 - 4(1)(5)=-16 (-)
2. Find the real roots of the equation. X²-2x+5=0
x² - 2x + 5 = 0
a = 1; b = -2; c = 5
.............................................
D = b² - 4ac
D = ( - 2)² - 4 . 1 . 5
D = 4 - 20
D = -16
Karena D < 0, maka akar-akarnya tidak real,
HP = { }
***************************************
Kelas 10
Pelajaran Matematika
Bab 2 Persamaan dan Fungsi Kuadrat
Kata kunci : -
Kode kategorisasi : 10.2.2
3. Find the value of m which the equation x^2+ (m – 3)x + 4 = 0 has two real roots.
• Persamaan Kuadrat
-
Nilai m agar x² + (m - 3)x + 4 = 0 memiliki 2 akar - akar real adalah m ≤ -1 atau m ≥ 7
• Pembahasan •
D ≥ 0 → Memiliki dua akar - akar reaL
x² + (m - 3)x + 4 = 0
a = 1
b = m - 3
c = 4
0 ≤ b² - 4ac
0 ≤ (m - 3)² - 4(1)(4)
0 ≤ m² - 6m + 9 - 16
0 ≤ m² - 6m - 7
0 ≤ (m + 1)(m - 7)
HP = { m ≤ -1 atau m ≥ 7 }
•••
-AL
Jawab:
m ≥ 7 atau m ≤ - 1
Penjelasan dengan langkah-langkah:
akan memiliki akar akar bilangan real jika D ≥ 0
bentuk umum persamaan kuadrat adalah ax² + bx + c = 0, maka dari soal diperoleh
a = 1
b = m - 3
c = 4
karena D ≥ 0, maka
D ≥ 0
b² - 4ac ≥ 0
(m-3)² - 4.1.4 ≥ 0
m² - 6m + 9 - 16 ≥ 0
m² - 6m - 7 ≥ 0
(m - 7)(m + 1) ≥ 0
maka didapat m ≥ 7 atau m ≤ -1
jadi, HP = {m | m ≥ 7 atau m ≤ - 1}
4. If the equation 4x2 - 12x + c = 0, where c is a constant, has two equal roots, find the value of c and the roots of the equation.
Jawaban:
(2x-3)(2x-3)
4x²-6x-6x+9
4x²-12x+9
c=9
5. Given one of the roots of the quadratic equation x 2 + kx – 3 = 0 is 3. Find the value of k.
Jawaban:
x²+kx-3=0
3²+3k-3=0
9+3k-3=0
3k+6=0
3k=-6
k=-2
barangkali ada yg ditanyalan dm dan follow ig @alwi_dj
6. The quadratics equation 2x^2 - 2(p - 4)x+p=0 has two distinct real roots, find the value of p.
Jawaban terlampir
Terimakasih
• Persamaan Kuadrat
-
Nilai p agar persamaan 2x² - 2(p - 4)x + p = 0 memiliki dua akar - akar real berbeda adalah {p | p < 2 atau p > 8 }
• Pembahasan •
2x² - 2(p - 4)x + p = 0
a = 2
b = -2(p - 4)
c = p
D > 0 → Dua akar real berbeda
0 < b² - 4ac
0 < (-2p + 8)² - 4(2)(p)
0 < 4p² - 32p + 64 - 8p
0 < 4p² - 40p + 64
0 < p² - 10p + 16
0 < (p - 2)(p - 8)
HP = {p | p < 2 atau p > 8 }
•••
-AL
7. The perimeter of a square is 45 cm find the length of are side of the square. Pls jawab :D
perimeter = 4s
45 cm /4
= 11.25 cm
?? idk hun maybe u should recheck it xx
8. The area of a square is 7225 cm? Find the length of a side of the square.
Area of square =7225cm²
Length of a side of the square
= √7225
= 85 cm
9. Find the unknown side and perimeter of square!
Jawaban:
[tex] \sqrt{49 } = 7[/tex]
10. the area of a square is 81 cm². Find the length of one side of the square!
Jawaban:
Luas persegi adalah 81 cm²,Maka panjang sisi (s) persegi tersebut adalah 9 cm
Penjelasan:
the area of a square is 81 cm². Find the length of one side of the square!=luas persegi adalah 81 cm². Hitunglah panjang salah satu sisi persegi tersebut!
moga membantuu
11. find the square root of 4
The Square root of 4 is 2, because 2x2 is 4 and it’s received in multiplying the exact same number so the result will be in the square root.
12. The area of a square is 64 cm2. Find the length of one side of the square! *
Jawab:
Penjelasan dengan langkah-langkah:
A=64cm²
A=side²
64cm²=side²
side=√64cm²
side=8cm
Square area formulaL = s x s
64 cm = s ^2
S= root 64
S= 8 cm
13. how to find the area of a square
find the length of the side, then make it to the power of two
14. If a square has an area of 64 square cm, find the correct perimeter for the square
Jawaban:
area of square = 64 cm^2
side length of square = √64 = 8 cm
perimeter for the square = 4 x 8 = 32 cm
15. By completing the square, prove that 2x^2-4x+3=0 is always positive for all real values of x
Jawab:
fungsi kuadrat selalu bernilai positif jika :
a> 0 dan D < 0
f(x) = 2x²-4x+3
a = 2 --> 2 > 0 , sehingga terbukti a > 0
D = b² - 4 ac
= (-4)² - 4(2)(3)
= 16 - 24
= -8 -----> -8 < 0, sehingga terbukti D < 0
16. the perimeter of a square is 20 cm find the length of one side of the square
Jawab: 5 cm
Penjelasan dengan langkah-langkah:
Panjang salah satu sisi bujur sangkar
Kll= 4×s
Maka;
S= kll/4
= 20 cm/4
= 5 cm
The perimeter of a square is 20 cm find the length of one side of the square!
Keliling bujur sangkar adalah 20 cm cari panjang salah satu sisinya!
PENDAHULUANA.DefinisiBujurSangkar/Persegi
Bujur sangkar atau persegi adalah suatu bangun datar dua dimensi yang dibentuk dari empat buah sisi (s) atau rusuk (a) yang sama panjang/kongruen dan memiliki empat buah sudut siku-siku(90°) di setiap sudutnya.
B.Rumus-RumusBujurSangkar/Persegi
[tex]K\ persegi = 4 \times s\ atau\ 4 \times a\\ L\ persegi = s^{2} atau a^{2}[/tex]
Keterangan:
s atau a = panjang sisi atau panjang rusuk persegi (m atau cm)
K persegi = keliling persegi (m atau cm)
Luas persegi = luas persegi (m² atau cm²)
PEMBAHASANDiketahui:
Keliling (K) persegi = 20 cm
Ditanya:
Panjang sisi (s) persegi = ?
Dijawab:
[tex]K\ persegi = 4 \times s\\ 20\ cm = 4 \times s\\ s = K\ persegi \div 4\\ s = 20\ cm \div 4\\ s = 5\ cm[/tex]
Kesimpulan:
Jadi, panjang sisi persegi itu adalah 5cm
Pelajari lebih lanjut:Definisi Persegi => https://brainly.co.id/tugas/4296082
Rumus Persegi => https://brainly.co.id/tugas/3351991
Contoh Soal Persegi => https://brainly.co.id/tugas/9193375
DETAIL JAWABANKelas: 2 SD, 3 SD
Mapel: Matematika
Bab: Kelas 2 Bab 4 Matematika - Bangun Datar Sederhana7, Kelas 3 Bab 10 Matematika Keliling dan Luas Persegi dan Persegi Panjang
Kode Kategorisasi: 2.2.4, 3.2.10
17. The Perimeter of a SQUARE is 20 cm. Find the length of one side of the square. Answer: _____ cm.
Jawaban:
The answer is 5 cm
Reason = square have 4 side. so 20 cm divided by 4
Jadikan jawaban terbaik ya
Terjemahan
Keliling sebuah persegi ialah 20 cm. Hitunglah panjang salah satu sisi persegi tersebut. Jawaban ____ cm.Diketahui
Keliling = 20 cm
Ditanyakan
sisi/s
Jawab
Keliling = 4 × s
20 = 4 × s
s = 20/4
s = 5 cm
18. Find the solution roots of the form 2x² + 7x + 3
Jawaban:
QUADRATICEQUATIONFind the solution roots of the form 2x² + 7x + 3
→{-1/2, -3}————————————————
SOLUTION![tex]2x + 7x + 3 = 0[/tex]
[tex]2x + 7x = - 3[/tex]
[tex] {x}^{2} + \frac{7}{2}x = - \frac{3}{2} [/tex]
[tex] {x}^{2} + \frac{7}{2}x + {( \frac{7}{4}) }^{2} = - \frac{3}{2} + \frac{49}{16} [/tex]
[tex] {(x + \frac{7}{4} })^{2} = \frac{ - 24 + 49}{16} [/tex]
[tex] {(x + \frac{7}{4} })^{2} = \frac{25}{16} [/tex]
[tex](x + \frac{7}{4}) = (tambah \: kurang) \sqrt{ \frac{25}{16} } [/tex]
[tex]x + \frac{7}{4} = (tambah \: kurang) \frac{5}{4} [/tex]
[tex] x_{1} = - \frac{7}{4} + \frac{5}{4} = - \frac{1}{2} [/tex]
[tex] x_{2} = - \frac{7}{4} - \frac{5}{4} = - 3 [/tex]
[tex] x_{1} = - \frac{1}{2} \: or \: x_{2} = - 3[/tex]
So,thesolutionrootsis{-1/2,-3}NOTE:Tambah kurang means '±'
————————————————
EXPLANATIONBefore you study this material, you should also have studied the root form material in chapter 1, because this QUESTION uses a little root form.
••
A one-variable quadratic equation is an equation whose highest power is two. In general, the form of a quadratic equation is ax² + bx + c = 0 where a ≠ 0, a, b, c, € R. The constants a,b,c in this equation, are called coefficients. Some examples of quadratic equations are:
3x - 7x + 5 = 0, x² - x + 12 = 0, x² - 9 = 0, 2x(x - 7) = 0,and others.The root of the quadratic equation of ax² + bx + c = 0 is the value of x that satisfies the equation. There are 3 ways to determine the roots of a quadratic equation, namely:
FactoringComplete the perfect squareQuadratic formula (Abc formula)The abc formula, like this:
x1,2 = -b ± √b² - 4ac / 2aCharacteristics of a quadratic equation based on the coefficients of its quadratic equation:
If x1 and x2 are the roots of the quadratic equation ax² + bx + c = 0, then:
x1 + x2 = -b / a and x1 x2 = c/aFor example a quadratic equation ax² + bx + c = 0 with its discriminant value is D = b² - 4ac then for D < 0 the quadratic equation has no roots, D = 0 the quadratic equation has twin roots, D > 0 the quadratic equation has two different roots .
————————————————
CONCLUSIONBASED ON THE EXPLANATION ABOVE THEN,:
the solution roots of the form 2x² + 7x + 3is{-1/2, -3}————————————————
LEARNMOREABOUT QUADRATIC FUNCTION
diketahui fungsi f(x)=2x²+4x-10. nilai dari f(5) adalah :
https://brainly.co.id/tugas/40948283HERE ARE THE MATERIAL ABOUT ROOT FORM, CLICK THIS LINK
https://brainly.co.id/tugas/46756815https://brainly.co.id/tugas/42856863https://brainly.co.id/tugas/42657285————————————————
ANSWER DETAILSSubject : Mathematics (English)Class / Grade: 9Category : JHSMaterial / Sub-Category : Chapter 2 - Quadratic Equation.Subject Code : 2Categorization : 9.2.2Keyword : Quadratic Equation.
#OptiTimCompetitionJawaban:
x = - ½ , - 3
Penjelasan:
Find the solution roots of the form 2x² + 7x + 3
======================
2x² + 7x + 3
( 2x + 1 ) ( x + 3 )
x = - ½ , - 3
19. The area of a square is 529 cm².Find the lenght of one side of a square!
Jawaban:
23 cm
Penjelasan dengan langkah-langkah:
Rumus luas persegi = s²
Luas = 529 cm²
[tex]sisi = \sqrt{529} = 23[/tex]
Sisi = 23 cm
Semoga membantu maaf kalo salah
20. the perimeter of a square is 20 cm find the length of one side of the square
Jawab: 5 cm
Penjelasan dengan langkah-langkah:
Panjang salah satu sisi bujur sangkar
Kll= 4×s
Maka;
S= kll/4
= 20 cm/4
= 5 cm
Side = 20 : 4 = 5 cm—Hope it helps for you!✨
0 komentar: