What is the area of the triangle shown below
1. What is the area of the triangle shown below
a = 5
b = 5
c = 8
Keliling
= a + b + c
= 5 + 5 + 8
= 18
s = 1/2 x keliling
s = 1/2 x 18
s = 9
Luas
= √(s(s - a)(s - b)(s - c))
= √(9(9 - 5)(9 - 5)(9 - 8))
= √(9 x 4 x 4 x 1)
= √144
= 12 satuan luas
2. What is the area of the right triangle shown below
ANSWER:
60.
Penjelasanya :
(theorema phytagoras) a=[tex]\sqrt{b^{2} -c^{2} }[/tex]
a= 17[tex]\sqrt{17^{2}-8^{2} } = \sqrt{289-64}[/tex]
a=[tex]\sqrt{225} =[/tex]15
(the area of the right triangle) :
1/2 x a x h
1/2 x 8 x 15
= 60
ur welcome:)
3. what is the area of the square on the third side of the triangle?
the triangle 40^2 + 10^2 = 1600 + 100 = 1700.
akar dari 1700 adalah 41 akar 19.
semoga bermanfaat.
maaf kalau salah.
4. The base of a triangle is longer than twice its corresponding height by 1 cm. The area of the triangle is 105 cm?. Find the height of the triangle!butuh cepat
Jawaban:
52,5
Penjelasan dengan langkah-langkah:
105:2 sorry if wrong
Jawab:
The height of the triangle is 10 cm.
Penjelasan dengan langkah-langkah:
If the area, base and height of that triangle are notated by A, b and h, then it is known that:
A = (1/2)bh
b = 2h+1
So:
A = (1/2) × (2h+1) × h
A = (1/2) × (2h²+h)
2A = 2h²+h
2×105 = 2h²+h
210 = 2h²+h
2h²+h-210 = 0
(2h+21)(h−10)=0
2h+21=0 or h−10=0
h = -21/2 or h = 10
The positive solution is h = 10, so the height of the triangle is 10 cm.
Proof:
If the height is 10 cm, then the base equals to 21 cm (2×10 + 1 = 21).
The area of the triangle:
A = (1/2)bh = (1/2)(21)(10) = (1/2)(210) = 105 cm². (correct!)
5. the area of the shaded triangle
mana ada yang mau jawab kalau loh pakek bahasa inggris .makanya pakek bahasa palembang dong
6. The formula of area of triangle
Jawaban:
[tex] \frac{1}{2} \times \: alas \times \: tinggi [/tex]
please understand
Penjelasan dengan langkah-langkah:
#Jadikan yang Jawabanmu
#yang Terbaik #^_^#
#Semoga membantu
7. what is the area of the square on the third side of the triangle yg nomor 16
[tex]c = \sqrt{ {10}^{2} + {40}^{2} } \\ = \sqrt{100 + 1600} \\ = \sqrt{1700} [/tex]
total area
[tex] = {10}^{2} + {40}^{2} + \sqrt{( {1700})^{2} } [/tex]
= 100 + 1600 + 1700
[tex]= 2400 cm^2[/tex]
8. The area of a triangle is 528cm2. the length of its base is 33cm. calculate the perpendicular height of the triangle.
Diketahui:
Luas segitiga = 528 cm²
Panjang alas = 33 cm
Tinggi = ?
[tex]luas \: = 528 \\ \frac{1}{2} \times a \times t = 528 \\ \frac{1}{2} \times 33 \times t = 528 \\ t = \frac{528 \times 2}{33} \\ t = 32[/tex]
Jadi, tinggi segitiga adalah 32 cm.
Jawab:
32
Penjelasan dengan langkah-langkah:
L=528
a= 33
L= a*t/2
528= 33*t/2
1056=33t
t= 1056/33
t=32
9. 21. What is the name of the shape belowA CubeB. RectangleC. TriangleD. Trapezium
Jawaban
Persegi
Persegi panjang
Seitiga.
Trapesium
Jawaban:
A.cube
Penjelasan:
maaf kalau salah
10. what is the area of the rectangle shown below?
Jawab:
Penjelasan dengan langkah-langkah:
The area= luas yaa
okee berarti sangat gampang kpk!
Luas persegi panjang= lebar x panjang
maka panjang= 5 3/4 =23/4 cm dan lebar=3 cm
L= pxl
= 23/4 x 3
=69/4
=17 1/4 cm atau 17,25 cm
11. (b) The area of triangle ABC is twice the area of triangle DBE.
Penjelasan dengan langkah-langkah:
[tex]area \: triangle \: abc = \frac{1}{2} \times base \times height \\ = \frac{1}{2} \times 8 \times 14 = 56 \: {cm}^{2} \\ area \: triangle \: abc \: = 2 \times area \: triangle \: dbe \\ 56 = 2 \times area \: triangle \: dbe \\ area \: triangle \: dbe \: = \frac{56}{2} = 28 \: {cm}^{2} [/tex]
12. c5.24 cmThe perimeter of the isosceles triangle is 60 cm. what is thearea of the triangle?a. 11c. 18b. 24d. 29( )
Jawab:
C. 18
Penjelasan dengan langkah-langkah:
Maaf kalau slaah
13. look at the right triangle below!what is the length of the side AC? berapa panjang AC?
Jawaban:
4√6
Penjelasan dengan langkah-langkah:
First,you must know the trigonometrybsics:
[tex] \sin( \alpha ) = \frac{o}{h} \\ \cos( \alpha ) = \frac{a}{h} \\ \tan( \alpha ) = \frac{o}{a} [/tex]
or simply SOH CAH TOA and the special angles (you can find the table in the internet)
Now,sinceyou know the adjacent (BD)of the lefttriangle,you can find the height (AD)using tan of Bwhich js60°
[tex] \tan(60) = \frac{ad}{4} = \sqrt{3} [/tex]
This leaves us with AD =4√3
Thenwe can substitute it into the sin of C
[tex] \sin(45) = \frac{4 \sqrt{3} }{ac} = \frac{ \sqrt{2} }{2} [/tex]
Then,you can operate this by cross multiplyingand get the final answer,which is AC =4√6
14. The area of the shaded triangle?
1/2 x 17 x16 136 Semoga membantu
Semoga bermanfaat. ...
15. father has frame in shape of triangle. the area of frame is 12 square meters. if the base of the triangular is 6 meters long, what is the height of the triangle. tolong dijawab ya dengan caranya. mau dikumpulin besok
the height is (area times two) divided by the base.
h = (12 × 2) ÷ 6 = 4
so the height of the triangle is 4 meters tall.Area = 1/2 x base x height
12 m ² = 1/2 x 6 m x height
12 m² = 3 m x height
Height = 12 m ÷ 3 m = 4 m
Jadikan jawaban tercerdas ya.
16. if one angle of a triangle is equal to the sum of other two angles then the triangle is-:i) an isoscales triangle.ii) an obtuse triangle.iii) an equilateral triangle.iv) a right triangle.
Jawaban:
iii) an equilateral triangle
mungkin
maafkalausalahya.
17. The perimeter of an isosceles triangle is 36 cm. If the base is 10 cm, the area of the triangle is .... cm2. (Pythagorean Theorem)
Penjelasan dengan langkah-langkah:
½ kali 10 kali 36 =
10 kali 36 : 2 =
360 : 2 = 180 cm²
maaf kalo salah ^_^
Pythagorean Theorem"In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides".
Question:
The perimeter of an isosceles triangle is 36 cm. If the base is 10 cm of length, the area of the triangle is ... cm²
Step by step:
Isosceles triangle have 36 cm of its perimeter. The perimeter of triangle is calculated by sum of each side.
Finding length of each leg (x):
36 cm = 10 + x + x
36 = 10 + 2x
26 = 2x
x = 13 cm.
To find the height of triangle, use pythagorean theorem. Let height is written by "y".
[tex]\displaystyle\\y = \sqrt{13^2 - 5^2}\\\\y = \sqrt{169 - 25}\\\\y = \sqrt{144}\\\\y = 12~\text{cm}[/tex]
Calculate the area:
[tex]\text{Area of triangle:}\\\\\boxed{\frac{\text{base}\times\text{height}}{2}}[/tex]
[tex]\displaystyle= \frac{10 \times 12}{2}\\\\= \frac{120}{2}\\\\= 60~\text{cm}^2[/tex]
Conclusion:
The area of an isosceles triangle with 10 cm length of base and 36 cm of its perimeter is 60 cm²
============================
Lesson Category:
(based of the Indonesian Curriculum)
Class: 8th grade of junior high schoolSubject: MathematicsLesson Category: Pythagorean TheoremLesson Code: 8.2.418. The area of a triangle is 30cm2 if the height is 6 cm what is the length of the base
Jawab:
5
Penjelasan dengan langkah-langkah:
19. The area of this triangle is 36 cm², the base id _______ cm.
Jawab: 8 cm
Penjelasan :
Jawaban:
luas segitiga tersebut adalah 36 cm², alasnya adalah 1.296 cm²
Penjelasan dengan langkah-langkah:
rumusnya: S x S
jadi 36 × 36 = 1.296 cm²
MAAF YA KAK KALO SALAH ☺️
20. Find the area of the shaded triangle.
Jawaban: 77
77
Penjelasan:
(11 x 14) : 2 = 77
maaf kalau salah
Jawaban:
Ini ya jawabannya.
Semoga membantu.
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